如何在python中对所有文件xml的循环结果求和答案

【问题标题】：How to sum result of loop for all file xml in python如何在python中对所有文件xml的循环结果求和
【发布时间】：2021-10-14 15:40:25
【问题描述】：

我是编程新手，遇到了问题。我有 4 个这样的文件

  <object>
    <pose>Damage</pose>
    <pose>Dent</pose>
    <pose>Damage</pose>
    <pose>Dent</pose>
    <pose>Damage</pose>
   </object>

我想计算所有文件中的损坏和凹痕数量。我已经这样做了，但没有得到我需要的结果。

            import os
            import xml.etree.ElementTree as ET
            from collections import defaultdict
            
            # files are in a sub folder where this script is being ran
            path = r"D:\Non_Documents\xml"
            for filename in os.listdir(path):
                # Only get xml files
                if not filename.endswith('.xml'): continue
                # I haven't been able to get it to work by just saying 'if filename.endswith('.xml')' only if not..
                fullname = os.path.join(path, filename)
                # This joins the path for each file it files so that python knows the full path / filename to trigger parser
                tree = ET.parse(fullname)
                # Parse the files..
                # print(tree)
                data = defaultdict(int)
                # Get the root of the XML tree structure
                root = tree.getroot()
                # print(fullname)
                for name in root.findall('.//name'):
                    data[name.text] += 1
                print(data)

这是我得到的结果

defaultdict(<class 'int'>, { 'Damage': 3, 'Dent': 2})
defaultdict(<class 'int'>, {'Dent': 29, 'Damage': 7})
defaultdict(<class 'int'>, { 'Damage': 6, 'Dent': 15})
defaultdict(<class 'int'>, {'Damage': 7, 'Dent': 19})

我该怎么做才能得到这样的结果？

defaultdict(<class 'int'>, {'Damage': 23, 'Dent': 65})

【问题讨论】：

您好，据我所知，变量data 和print 的声明都在第一个for 循环中。这是行不通的，因为这样会为每个文件计算、打印和重置data 的内容。您应该看到将data 的声明移到循环之前，将print 的声明移到循环之后。

标签： python python-3.x dictionary for-loop python-requests

【解决方案1】：

将你所有的字典添加到下面这样的列表中，

a = [defaultdict(<class 'int'>, { 'Damage': 3, 'Dent': 2}),
defaultdict(<class 'int'>, {'Dent': 29, 'Damage': 7}),
defaultdict(<class 'int'>, { 'Damage': 6, 'Dent': 15}),
defaultdict(<class 'int'>, {'Damage': 7, 'Dent': 19})]

使用下面的代码返回预期的输出，

sumDict = {'Damage': 0, 'Dent': 0}
for i in a:
    for m,n in i.items():
        sumDict.update({m:sumDict[m]+n})

输出将是，

{'Damage': 23, 'Dent': 65}

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【讨论】：

【解决方案2】：

我按照您的预期修改了您的代码和确切的结果。你可以试试下面的代码sn-p。

import os
import xml.etree.ElementTree as ET
from collections import defaultdict

# files are in a sub folder where this script is being ran
path = r"D:\Non_Documents\xml"
data_list = []
for filename in os.listdir(path):
    # Only get xml files
    if not filename.endswith('.xml'): continue
    # I haven't been able to get it to work by just saying 'if filename.endswith('.xml')' only if not..
    fullname = os.path.join(path, filename)
    # This joins the path for each file it files so that python knows the full path / filename to trigger parser
    tree = ET.parse(fullname)
    # Parse the files..
    # print(tree)
    data = defaultdict(int)
    # Get the root of the XML tree structure
    root = tree.getroot()
    # print(fullname)
    for name in root.findall('.//name'):
        data[name.text] += 1
    data_list.append(data)

result = defaultdict(int)

for data in data_list:
    for key, value in data.items():
        result[key] += value

print(result)

输出：

defaultdict(<class 'int'>, {'Damage': 30, 'Dent': 20})

【讨论】：