不理解 Python 中的错误消息：AttributeError: 'dict' object has no attribute 'append'答案

【问题标题】：Not understanding error message in Python: AttributeError: 'dict' object has no attribute 'append'不理解 Python 中的错误消息：AttributeError: 'dict' object has no attribute 'append'
【发布时间】：2021-12-26 03:46:21
【问题描述】：

Task I need to do

class Restaurant:
    def __init__(self,
                name, website, cuisine):
        self.name = name
        self.website = website
        self.cuisine = cuisine
    
dominoes = Restaurant("Dominoes", "www.dominoes.co.uk", "pizza")
yosushi = Restaurant("Yo Sushi!", "www.yosushi.co.uk", "sushi")
fiveguys = Restaurant("Five Guys", "www.fiveguys.co.uk" ,"burger")

restaurants = dict()
restaurants["Dominoes"] = dominoes
restaurants["Yo Sushi!"] = yosushi
restaurants["Five Guys"] = fiveguys

in_loop = True

while in_loop:

    print("CS1822 Restaurant DB")

    print("1. Display restaurant list")
    print("2. Add a restaurant")
    print("3. Exit")

    choice = input("Please enter your choice: ")

    if choice == "1":
        for name in restaurants:
            restaurant = restaurants[name]
            print(name, "-", restaurant.website, "-", restaurant.cuisine)
            
    elif choice == "2":
        name = input("Enter restaurant name: ")
        website = input("Enter website: ")
        cuisine = input("Enter cuisine: ")
        x = Restaurant(name, website, cuisine)
        restaurants.append(x)
    
    else:
        print("Goodbye!")
        break

我不明白如何解决错误信息：

运行错误回溯（最近一次通话最后）：文件“tester.python3”，第 55 行，在餐厅.append(x) AttributeError: 'dict' 对象没有属性 'append'

我正在尝试将用户输入的餐厅及其功能添加到餐厅列表中。

【问题讨论】：

append() 仅适用于列表。字典没有append() 方法。这回答了你的问题了吗？ Python AttributeError: 'dict' object has no attribute 'append'
我需要删除 dict() 并改为创建一个列表吗？
视情况而定。你需要使用字典吗？如果是这样，您可以查看我之前评论中的链接。否则，只需切换到一个列表。
不，我不认为我需要使用字典，我不确定如何创建列表，但我会检查您的链接并尝试解决

标签： python list append

【解决方案1】：

class Restaurant:
    def __init__(self,
                 name, website, cuisine):
        self.name = name
        self.website = website
        self.cuisine = cuisine


dominoes = Restaurant("Dominoes", "www.dominoes.co.uk", "pizza")
yosushi = Restaurant("Yo Sushi!", "www.yosushi.co.uk", "sushi")
fiveguys = Restaurant("Five Guys", "www.fiveguys.co.uk", "burger")

restaurants = dict()
restaurants["Dominoes"] = dominoes
restaurants["Yo Sushi!"] = yosushi
restaurants["Five Guys"] = fiveguys

in_loop = True

while in_loop:

    print("CS1822 Restaurant DB")

    print("1. Display restaurant list")
    print("2. Add a restaurant")
    print("3. Exit")

    choice = input("Please enter your choice: ")

    if choice == "1":
        for name in restaurants:
            restaurant = restaurants[name]
            print(name, "-", restaurant.website, "-", restaurant.cuisine)

    elif choice == "2":
        name = input("Enter restaurant name: ")
        website = input("Enter website: ")
        cuisine = input("Enter cuisine: ")
        x = Restaurant(name, website, cuisine)
        restaurants[name]=x ### You can't use 'append()', because you are using 'dict' in this code, so for 'dict' you need this string

    else:
        print("Goodbye!")
        break

【讨论】：

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