随机选择类别内的字典条目数？

Question

所以我设法生成了一个“记分牌”字典：

{
Player1: '10 1st',
Player2: '10 1st',
Player3: '10 1st',
Player4: '10 1st',
Player5: '10 1st',
Player6: '8 2nd',
Player7: '8 2nd',
Player8: '8 2nd',
Player9: '8 2nd',
Player10: '5 3rd',
Player11: '5 3rd',
Player12: '5 3rd'
}

但现在我不知道如何检查键字符串中的第 1/2/3 个，然后从每个“类别（第 1、第 2、第 3）”中随机选择一定数量的条目以输出新字典，例如：

如果我想随机选择 3 个1st、2 个2nd 和3rd 条目，新字典将为

{
Player2: '10 1st',
Player4: '10 1st',
Player5: '10 1st',
Player6: '8 2nd',
Player9: '8 2nd',
Player11: '5 3rd',
Player12: '5 3rd'
}

感谢阅读..

Answer 1

也许将对象转换为条目的随机数组，然后使用 <Array>.filter 过滤出每种类型的单独数组，然后在每个数组上使用 <Array>.slice 以从中获取 x 数量的条目，然后使用重构对象更新的条目：

使用numFirst = 3, numSecond = 2, numThird = 2的示例：

const data = {
Player1: '10 1st',
Player2: '10 1st',
Player3: '10 1st',
Player4: '10 1st',
Player5: '10 1st',
Player6: '8 2nd',
Player7: '8 2nd',
Player8: '8 2nd',
Player9: '8 2nd',
Player10: '5 3rd',
Player11: '5 3rd',
Player12: '5 3rd'
}

let numFirst = 3;
let numSecond = 2;
let numThird = 2;

const entries = Object.entries(data).sort(() => .5 - Math.random());
const first = entries.filter(a => a[1].endsWith('1st')).slice(0, numFirst);
const second = entries.filter(a => a[1].endsWith('2nd')).slice(0, numSecond);
const third = entries.filter(a => a[1].endsWith('3rd')).slice(0, numThird);

const filteredData = Object.fromEntries([...first, ...second, ...third]);
console.log(filteredData);