在 pandas 列中替换多个术语的优雅而有效的方法答案

【问题标题】：Elegant and efficient way to replace multiple terms in a pandas column在 pandas 列中替换多个术语的优雅而有效的方法
【发布时间】：2021-06-28 12:30:27
【问题描述】：

我想替换数据框列中的多个值，如下所示

df['label'] = ['Sodium', 'Bicarbonate', 'White Blood Cells', 'Hemoglobin',
       'Glucose', 'Lactate', 'pH', 'Potassium, Whole Blood',
       'Sodium, Whole Blood', 'Lactate Dehydrogenase (LD)',
       'Bilirubin, Direct', 'Alkaline Phosphatase',
       'Alanine Aminotransferase (ALT)',
       'Asparate Aminotransferase (AST)', 'Potassium', 'Phosphate',
       'Creatinine', 'C-Reactive Protein', 'pCO2',
       'Calculated Bicarbonate, Whole Blood', 'Bilirubin, Total',
       'Albumin', 'Bilirubin, Indirect', 'Urine Volume', 'WBC Count',
       'Urine Volume, Total', 'Phosphate, Body Fluid']

在下面的代码中，我试图用 Sodium 替换 Sodium 和 Sodium, Whole Blood。

同样，我对其余的测量也是如此

df['label'] = df['label'].replace(dict.fromkeys(['Sodium','Sodium, Whole Blood'], 'Sodium'))
df['label'] = df['label'].replace(dict.fromkeys(['Bicarbonate','Calculated Bicarbonate, Whole Blood'], 'Bicarbonate'))
df['label'] = df['label'].replace(dict.fromkeys(['Bicarbonate','Bilirubin, Indirect'], 'Bicarbonate'))
df['label'] = df['label'].replace(dict.fromkeys(['Bilirubin, Direct','Bilirubin, Total','Calculated Bicarbonate, Whole Blood'], 'Bilirubin'))
df['label'] = df['label'].replace(dict.fromkeys(['Urine Volume, Total','Urine Volume'], 'Urine Volume'))
df['label'] = df['label'].replace(dict.fromkeys(['White Blood Cells','WBC Count'], 'WBC'))
df['label'] = df['label'].replace(dict.fromkeys(['Potassium, Whole Blood','Potassium'], 'Potassium'))
df['label'] = df['label'].replace(dict.fromkeys(['Phosphate','Phosphate, Body Fluid'], 'Phosphate'))

虽然上面的代码工作得很好，有没有其他有效的方法可以有效地替换而不是多次重复同一行代码？

【问题讨论】：

标签： python pandas dataframe dictionary series

【解决方案1】：

一种方法是创建大字典并替换一次：

# add more of your stuff here
lst = [(['Sodium','Sodium, Whole Blood'], 'Sodium'),
       (['Bicarbonate','Calculated Bicarbonate, Whole Blood'], 'Bicarbonate')
      ]

repl_dict = {}
for x,y in lst:
    repl_dict.update(dict.fromkeys(x,y))

df['label'] = df['label'].replace(repl_dict)

【讨论】：