在一个键的多个值的字典中添加列表或字典 - Python

Question

第一次在这里发帖，如有不妥请见谅。 我有 2 个字典，其中键和列表作为值。我需要将列表分配给字典中与其他字典 2 匹配的列表元素。

Dictionary 1
{'S': ['Close Coupled', 'Wall Hung', 'Btw'], 'E':['Bifold', 'Hinge', 'Sliding', 'Pivot']}

Dictionary 2
{'Close Coupled': ['Close Coupled Contract', 'Close Coupled Open Back', 'Close Coupled Open Back Rimless'], 'Wall Hung': ['Wall Hung Contract', 'Wall Hung Rimless'],'Btw': ['BTW Contract', 'BTW Rimless'], 'Bifold': ['700', '800', '900', '1000'], 'Hinge': ['700', '800', '900', '1000'], 'Sliding': ['700', '800', '900', '1000'], 'Pivot': ['700', '800', '900', '1000']} 

Result I am trying to get is.
{'S': {'Close Coupled':['Close Coupled Contract', 'Close Coupled Open Back', 'Close Coupled Open Back Rimless'], 'Wall Hung': ['Wall Hung Contract', 'Wall Hung Rimless'], 'Btw': ['BTW Contract', 'BTW Rimless'], 'E': 'Bifold':['700', '800', '900', '1000'], 'Hinge':['700', '800', '900', '1000'],'Sliding':['700', '800', '900', '1000'], 'Pivot':['700', '800', '900', '1000']}

在他之后，我有另一本字典，将以同样的方式添加。它就像一个树结构或嵌套，但我无法建立我的逻辑来将字典分配给第一个字典中列表的每个匹配元素。

如果不清楚；请让我知道我会尝试更好地解释它。

谢谢

Answer 1

我认为我没有正确理解您的问题。但是请检查此代码，如果它不适合您的需要，请告诉我。

d1= {'S': ['Close Coupled', 'Wall Hung', 'Btw'], 'E':['Bifold', 'Hinge', 'Sliding', 'Pivot']}

d2= {'Close Coupled': ['Close Coupled Contract', 'Close Coupled Open Back', 'Close Coupled Open Back Rimless'], 'Wall Hung': ['Wall Hung Contract', 'Wall Hung Rimless'],'Btw': ['BTW Contract', 'BTW Rimless'], 'Bifold': ['700', '800', '900', '1000'], 'Hinge': ['700', '800', '900', '1000'], 'Sliding': ['700', '800', '900', '1000'], 'Pivot': ['700', '800', '900', '1000']}

final_dict= {} # create a dictionary to store the final answer
for item in d1:
    temp= dict() # temporary dictionary
    for i in item d1[item]:
        temp[i]= d2[i]
    final_dict[item]= temp

输出
打印（final_dict）

{'E': {'Bifold': ['700', '800', '900', '1000'],
  'Hinge': ['700', '800', '900', '1000'],
  'Pivot': ['700', '800', '900', '1000'],
  'Sliding': ['700', '800', '900', '1000']},
 'S': {'Btw': ['BTW Contract', 'BTW Rimless'],
  'Close Coupled': ['Close Coupled Contract',
   'Close Coupled Open Back',
   'Close Coupled Open Back Rimless'],
  'Wall Hung': ['Wall Hung Contract', 'Wall Hung Rimless']}} `

Answer 2

你可以使用dict理解来做到这一点：

{keys : {m : d2.get(m) for m in values} for keys, values in d1.items()}


{'S': {'Close Coupled': ['Close Coupled Contract',
   'Close Coupled Open Back',
   'Close Coupled Open Back Rimless'],
  'Wall Hung': ['Wall Hung Contract', 'Wall Hung Rimless'],
  'Btw': ['BTW Contract', 'BTW Rimless']},
 'E': {'Bifold': ['700', '800', '900', '1000'],
  'Hinge': ['700', '800', '900', '1000'],
  'Sliding': ['700', '800', '900', '1000'],
  'Pivot': ['700', '800', '900', '1000']}}

数据：

d1 = {'S': ['Close Coupled', 'Wall Hung', 'Btw'], 'E':['Bifold', 'Hinge', 'Sliding', 'Pivot']}
d2 = {'Close Coupled': ['Close Coupled Contract', 'Close Coupled Open Back', 'Close Coupled Open Back Rimless'], 'Wall Hung': ['Wall Hung Contract', 'Wall Hung Rimless'],'Btw': ['BTW Contract', 'BTW Rimless'], 'Bifold': ['700', '800', '900', '1000'], 'Hinge': ['700', '800', '900', '1000'], 'Sliding': ['700', '800', '900', '1000'], 'Pivot': ['700', '800', '900', '1000']}

Answer 3

一种方法是遍历您的第一个字典并从您的第二个字典中获取与同名键对应的列表。例如：

d1 = {'S': ['Close Coupled', 'Wall Hung', 'Btw'], 'E':['Bifold', 'Hinge', 'Sliding', 'Pivot']}
d2 = {'Close Coupled': ['Close Coupled Contract', 'Close Coupled Open Back', 'Close Coupled Open Back Rimless'], 'Wall Hung': ['Wall Hung Contract', 'Wall Hung Rimless'],'Btw': ['BTW Contract', 'BTW Rimless'], 'Bifold': ['700', '800', '900', '1000'], 'Hinge': ['700', '800', '900', '1000'], 'Sliding': ['700', '800', '900', '1000'], 'Pivot': ['700', '800', '900', '1000']}
result = dict()

for key, values in d1.items():
    result[key] = dict()
    for value in values:
        result[key][value] = d2[value]

print(result)

# OUTPUT (print does not output indented results shown here for readability only)
# {
#      'S': {
#          'Close Coupled': ['Close Coupled Contract', 'Close Coupled Open Back', 'Close Coupled Open Back Rimless'],
#          'Btw': ['BTW Contract', 'BTW Rimless'],
#          'Wall Hung': ['Wall Hung Contract', 'Wall Hung Rimless']
#          },
#      'E': {
#          'Bifold': ['700', '800', '900', '1000'],
#          'Hinge': ['700', '800', '900', '1000'],
#          'Sliding': ['700', '800', '900', '1000'],
#          'Pivot': ['700', '800', '900', '1000']
#          }
# }