MatLab OOP 不改变属性

Question

我有一个带有“下一个状态”属性的 matlab 类。

我在类中定义了以下函数：

function obj = decideNextAction(obj)
            obj.current_patch_quality
            % Important, rand is redeclared in the two calls. So it may be
            % that rand < current_patch_quality in the first if and greater
            % than in the second if
            if(rand > obj.current_patch_quality)
                obj.next_action = 1;
            elseif(rand < obj.current_patch_quality)
                obj.next_action = 3;
            else
                obj.next_action = 2;
            end   


        end

应该将实例属性重新定义为 1、2 或 3。但是，我做了一些试验，似乎该函数返回了一个带有修改后实例的新对象，但没有修改原始对象。有什么建议吗？

>> x = recruit([0 0])

x =

  recruit with properties:

             nest_location: [0 0]
    current_patch_location: []
     current_patch_quality: 0
               next_action: []

>> x.decideNextAction

ans =

     0


ans =

  recruit with properties:

             nest_location: [0 0]
    current_patch_location: []
     current_patch_quality: 0
               next_action: 1

>> x

x =

  recruit with properties:

             nest_location: [0 0]
    current_patch_location: []
     current_patch_quality: 0
               next_action: []

>>

Answer 1

你必须在classdef中使用handle class：

classdef myclass < handle

如果你使用value class，那么一定是：

x = x.decideNextAction();