从 Bash 中的特定文件调用相同命名的函数

Question

如果我有 3 个单独的文件，每个文件都有同名的函数：

# switch1.sh

switch()
{
    echo "SWITCH 1"
}

# switch2.sh

switch()
{
    echo "SWITCH 2"
}

# switch3.sh

switch()
{
    echo "SWITCH 3"
}

有没有办法在不使函数名称唯一的情况下指定调用哪个函数？

Answer 1

@Barmar 是对的，“当您获取每个文件时，它的功能会替换前一个。”

对于任何对这个问题的目的感兴趣的人，我的目标是在这个 bash 脚本中获得某种面向对象的理智：

switch1.s​​h

switch()
{
    echo "switch1"
}

check_administratorpassword()
{
    file="switch1.sh"
    description="Administrator password required to change system-wide preferences"
    switch=$(switch)

    if [ -n "$(security authorizationdb read system.preferences 2> /dev/null | grep -A1 shared | grep -E '(true|false)' | grep 'false')" ]; then 
        return 0
    else 
        return 1
    fi
}

switch2.sh

switch()
{
    echo "switch2"

    if which brew > /dev/null; then
        read -p "Check for Homebrew updates? (y/n): " input
        if [[ $input == "Y" || $input == "y" ]]; then
            echo "Checking for Homebrew updates..."
            brew update
        elif [[ $input == "N" || $input == "n" ]]; then
            :
        else
            echo "Not a recognized input."
            switch_homebrewinstall
        fi
    else
        echo "Homebrew is not installed."
        read -p "Install Homebrew? (y/n): " input
        if [[ $input == "Y" || $input == "y" ]]; then
             # Install Homebrew, TODO: Find secure way to download homebrew
             echo -e "Installing Homebrew..."
            /usr/bin/ruby -e "$(curl -fsSL https://raw.githubusercontent.com/Homebrew/install/master/install)"
        elif [[ $input == "N" || $input == "n" ]]; then
            :
        else
            echo "Not a recognized input."
            switch_homebrewinstall
        fi
    fi
    unset input
}

check_homebrewinstall()
{
    file="switch2.sh"
    description="Homebrew is installed."
    switch=$(switch)

    if which brew > /dev/null; then
        return 0
    else
        return 1
    fi
}

switch3.sh

switch()
{
    echo "switch3"
}

check_javainstall()
{
    file="switch3.sh"
    description="Java is installed."
    switch=$(switch)

    path=$(type -p java)
    if [[ $path = /dev/null ]]; then
        return 1
    else
        return 0
    fi
    unset path
}

switch-test.sh

source switch1.sh
source switch2.sh
source switch3.sh

declare -a checkArray
checkArray[1]=check_administratorpassword
checkArray[2]=check_homebrewinstall
checkArray[3]=check_javainstall

for i in "${!checkArray[@]}"; do   
    ${checkArray[$i]}
    if [ $? -eq 1 ]; then
        echo -e "\xE2\x9C\x97 ${description}"
    else
        echo -e "\xE2\x9C\x93 ${description}"
    fi
    source "${file}"
    switch
done

输出

$ bash switch-test.sh
✗ Administrator password required to change system-wide preferences
switch1
✓ Homebrew is installed.
switch2
✓ Java is installed.
switch3

这个文件是在 switch 函数被调用之前重新获取资源的，给人一种奇怪的错觉，认为它是 OOP。我不建议这样做，因为没有人查看您的代码会认为这是正在发生的事情，但它有点酷。