显示三元运算符的颜色

Question

如果我的三元运算符返回为真，我试图显示一种颜色，如果返回为假，则显示另一种颜色。操作员正在工作，但有一件事情发生了。双引号内的代码显示而不是实际颜色本身。有谁知道如何解决这个问题？

$msg .= ($row['opened'] == '0') ? "background-color: #DDEDFF;" : "background-color: #000000;"; 

编辑！！！ - 这些是我的$msg 变量出现的唯一时间

public function getLatestMessage ($userLoggedIn, $user2) {

    $query = $this->con->prepare('SELECT body, user_to, opened, date FROM messages WHERE 
        user_to = ? AND user_from = ? OR user_to = ? AND user_from = ? ORDER BY id DESC LIMIT 1'); 
    $query->bind_param("ssss", $userLoggedIn, $user2, $user2, $userLoggedIn);
    $query->execute();
    $query_result = $query->get_result();

    $msg = ""; //to hold the message data

    if ($row = $query_result->fetch_assoc()) { //don't need a while here because we've limited the query to one record

        //Timeframe
        $date_time_now = date("Y-m-d H:i:s");
        $start_date = new DateTime($row['date']); //Time of post
        $end_date = new DateTime($date_time_now); //Current time
        $interval = $start_date->diff($end_date); //Difference between dates 
        if($interval->y >= 1) {
            if($interval->y == 1)
                $time_message = $interval->y . "yr"; //1 year ago
            else 
                $time_message = $interval->y . "yrs"; //1+ year ago
        }
        else if ($interval-> m >= 1) {
            if($interval->d == 0) {
                $days = " ago";
            }
            else if($interval->d == 1) {
                $days = $interval->d . "d";
            }
            else {
                $days = $interval->d . "d";
            }

            if($interval->m == 1) {
                $time_message = $interval->m . "month";
            }
            else {
                $time_message = $interval->m . "months";
            }

        }
        else if($interval->d >= 1) {
            if($interval->d == 1) {
                $time_message = "Yesterday";
            }
            else {
                $time_message = $interval->d . "d ";
            }
        }
        else if($interval->h >= 1) {
            if($interval->h == 1) {
                $time_message = $interval->h . "hr";
            }
            else {
                $time_message = $interval->h . "hrs";
            }
        }
        else if($interval->i >= 1) {
            if($interval->i == 1) {
                $time_message = $interval->i . "m";
            }
            else {
                $time_message = $interval->i . "m";
            }
        }
        else {
            if($interval->s < 30) {
                $time_message = "Just now";
            }
            else {
                $time_message = $interval->s . " seconds ago";
            }
        }

        $msg .= ($row['user_to'] == $userLoggedIn) ? "They said: " : "You said: ";
        $msg .= '&nbsp;&nbsp;';
        $msg .= $body = $row['body'];
        $msg .= '&nbsp;&nbsp;';
        $msg .= $time_message ;
        $msg .= '&nbsp;&nbsp;';
        $msg .= ($row['opened'] == '0') ? "background-color: #DDEDFF;" : "background-color: #000000;";
    }

    return $msg;
}

Answer 1

您的代码完全按照您所说的做：输出一个字符串，上面写着“background-color: ...”。

浏览器如何知道您想用该颜色对文本进行样式，而不是向用户呈现这些文字？

您需要为浏览器指定这是您提供的样式。

代替

        $msg .= ($row['opened'] == '0') ? "background-color: #DDEDFF;" : "background-color: #000000;";

尝试类似：

 $color = $row['opened'] == '0' ? "#DDEDFF" : "#000000";
 $msg .= "<span style='background-color:$color'>THE TEXT YOU WANT TO COLORIZE</span>";

完整示例

<?php

function getLatestMessage($opened) {

    $color = $opened ? "#DDEDFF" : "#000000";
    $msg = "<span style='background-color:$color'>THE TEXT YOU WANT TO COLORIZE</span>";
    return $msg;
}

echo getLatestMessage(true);
echo getLatestMessage(false);

?>