【发布时间】:2021-07-25 10:45:04
【问题描述】:
我有一个嵌套对象,它由function 中的基础数据生成。生成的数据有几个levels深(data_tree)
要输入每个children,我使用recursive function。
我想要的是addchildren2项的数据到children和remove children2
接下来我以JSON 格式展示data_tree,以了解structure 是如何的。请记住,data_tree 是 object
{
"data_tree": [
{
"code":"PE",
"country":"Peruvian",
"language" :"spanish",
"children":[
{
"code": "DEP1" ,
"region":"Tumbes",
"children": [
{
"code": "PRO1",
"province":"Contralmirante Villar"
}
],
"children2": [
{
"code": "PRO2",
"province":"Zarumilla "
}
]
},
{
"code": "DEP2" ,
"region":"Piura",
"children": [],
"children2": [
{
"code": "PRO4",
"province" :"Paita"
},
{
"code": "PRO5",
"province":"Sullana"
}
]
},
{
"code": "DEP3" ,
"region":"Lambayeque"
}
],
"children2":[
{
"code": "DEP4" ,
"region":"La Libertad"
},
{
"code": "DEP5" ,
"region":"Lima"
}
]
},
{
"code":"EC"
"country":"Ecuador",
"language" :"spanish",
"children":[
{
"code": "4" ,
"province":"Quito"
},
{
"code": "5" ,
"province":"Guayaquil"
}
],
"children2":[]
}
]
}
我使用的recursive function 是:如果它有孩子,它会不断迭代。
$traverse = function ($data_tree) use (&$traverse) {
foreach ($data_tree as &$node) {
if (empty($node->children)) { //if the children is empty
unset($node->children); //I remove the children to add it with the data of children2
$node->children =$node->children2;
unset($node->children2);//I delete children2
}else{
//in case I have data, how do I add the data from dechildren2 to children?
}
$traverse($node->children);
}
};
$traverse($data_tree);
return $data_tree;
【问题讨论】: