【发布时间】:2013-11-07 04:29:18
【问题描述】:
我正在尝试从使用 BFS 实现的这段代码开始解决 DFS 的 8 谜题问题。最简单的方法是什么?我研究过的所有代码要么正常工作,要么不完整,这让我比以前更加困惑。
import java.util.HashMap;
import java.util.LinkedList;
import java.util.Map;
import java.util.Queue;
class EightPuzzle {
Queue<String> agenda = new LinkedList<String>(); // Use of Queue Implemented using LinkedList for Storing All the Nodes in BFS.
Map<String,Integer> stateDepth = new HashMap<String, Integer>(); // HashMap is used to ignore repeated nodes
Map<String,String> stateHistory = new HashMap<String,String>(); // relates each position to its predecessor
public static void main(String args[]){
String str="087465132"; // Input the Board State as a String with 0 as the Blank Space
EightPuzzle e = new EightPuzzle(); // New Instance of the EightPuzzle
e.add(str, null); // Add the Initial State
while(!e.agenda.isEmpty()){
String currentState = e.agenda.remove();
e.up(currentState); // Move the blank space up and add new state to queue
e.down(currentState); // Move the blank space down
e.left(currentState); // Move left
e.right(currentState); // Move right and remove the current node from Queue
}
System.out.println("Solution doesn't exist");
}
//Add method to add the new string to the Map and Queue
void add(String newState, String oldState){
if(!stateDepth.containsKey(newState)){
int newValue = oldState == null ? 0 : stateDepth.get(oldState) + 1;
stateDepth.put(newState, newValue);
agenda.add(newState);
stateHistory.put(newState, oldState);
}
}
/* Each of the Methods below Takes the Current State of Board as String. Then the operation to move the blank space is done if possible.
After that the new string is added to the map and queue.If it is the Goal State then the Program Terminates.
*/
void up(String currentState){
int a = currentState.indexOf("0");
if(a>2){
String nextState = currentState.substring(0,a-3)+"0"+currentState.substring(a-2,a)+currentState.charAt(a-3)+currentState.substring(a+1);
checkCompletion(currentState, nextState);
}
}
void down(String currentState){
int a = currentState.indexOf("0");
if(a<6){
String nextState = currentState.substring(0,a)+currentState.substring(a+3,a+4)+currentState.substring(a+1,a+3)+"0"+currentState.substring(a+4);
checkCompletion(currentState, nextState);
}
}
void left(String currentState){
int a = currentState.indexOf("0");
if(a!=0 && a!=3 && a!=6){
String nextState = currentState.substring(0,a-1)+"0"+currentState.charAt(a-1)+currentState.substring(a+1);
checkCompletion(currentState, nextState);
}
}
void right(String currentState){
int a = currentState.indexOf("0");
if(a!=2 && a!=5 && a!=8){
String nextState = currentState.substring(0,a)+currentState.charAt(a+1)+"0"+currentState.substring(a+2);
checkCompletion(currentState, nextState);
}
}
private void checkCompletion(String oldState, String newState) {
add(newState, oldState);
if(newState.equals("123456780")) {
System.out.println("Solution Exists at Level "+stateDepth.get(newState)+" of the tree");
String traceState = newState;
while (traceState != null) {
System.out.println(traceState + " at " + stateDepth.get(traceState));
traceState = stateHistory.get(traceState);
}
System.exit(0);
}
}
}
【问题讨论】:
标签: java breadth-first-search depth-first-search sliding-tile-puzzle