如果答案无效，程序将不会再次打印和循环答案

【问题标题】：Program won't print and loop again if the answer invalid如果答案无效，程序将不会再次打印和循环
【发布时间】：2018-04-09 22:57:32
【问题描述】：

我有这个程序，我想检查所选场地是否可以容纳人数 (noPeople)。如果无法容纳人数，则返回 FALSE，否则返回 TRUE。

print('''
    [1] vip room(10 person)            [4]Banquet Hall(200 person)
    [2] executive room(30 person)      [5]Chamber Hall(500 person)
    [3] pool site(50 person)           [6]Concert Hall(1000 person)
    ''')
def validateVenue(choice,venueList,noPeople):

    if choice == '1':
        noPeople <= (int(venueList[0]['VIP Room']))
        return True

    elif choice == '2':
        noPeople <= (int(venueList[0]['Executive Room']))
        return True

    elif choice == '3':
        noPeople <= (int(venueList[0]['Pool Site']))
        return True

    elif choice == '4':
        noPeople <= (int(venueList[0]['Banquet Hall']))
        return True

    elif choice == '5':
        noPeople <= (int(venueList[0]['Chamber Hall']))
        return True

    elif choice == '6':
        noPeople <= (int(venueList[0]['Concert Hall']))
        return True

    else:
        print('Invalid venue, please choose again.')
        return False

while True:
    noPeople = int(input('people:'))
    venueList = [{'VIP Room':10,'Executive Room':30,'Pool Site':50,'Banquet Hall':200,'Chamber Hall':500,'Concert Hall':1000}]
    choice = input('Please select a venue:')

    if validateVenue(choice,venueList,noPeople):
        break

而且我的程序似乎不想循环，即使房间不能容纳足够的人，它也不会打印无效的场地。

[1] vip room(10 person)            [4]Banquet Hall(200 person)
[2] executive room(30 person)      [5]Chamber Hall(500 person)
[3] pool site(50 person)           [6]Concert Hall(1000 person)

people:50
Please select a venue:1
>>>

是我遗漏了什么还是我做错了。任何建议和帮助。谢谢

【问题讨论】：

请正确缩进。由于continue不在循环内，这似乎只会给出语法错误。
另外，我不知道你认为像noPeople <= (int(venueList[0]['VIP Room'])) 这样的语句是做什么的，但是在不做任何结果的情况下进行这样的比较不会有任何效果。
我已经编辑了问题

标签： python python-3.x

【解决方案1】：

你犯了一些小错误。缺少if 和一个错误的最后一个案例。

print('''
    [1] vip room(10 person)            [4]Banquet Hall(200 person)
    [2] executive room(30 person)      [5]Chamber Hall(500 person)
    [3] pool site(50 person)           [6]Concert Hall(1000 person)
    ''')
def validateVenue(choice,venueList,noPeople):

    if choice == '1':
        if noPeople <= (int(venueList[0]['VIP Room'])):
            return True

    elif choice == '2':
        if noPeople <= (int(venueList[0]['Executive Room'])):
            return True

    elif choice == '3':
        if noPeople <= (int(venueList[0]['Pool Site'])):
            return True

    elif choice == '4':
        if noPeople <= (int(venueList[0]['Banquet Hall'])):
            return True

    elif choice == '5':
        if noPeople <= (int(venueList[0]['Chamber Hall'])):
            return True

    elif choice == '6':
        if noPeople <= (int(venueList[0]['Concert Hall'])):
            return True

    print('Invalid venue, please choose again.')
    return False

venueList = [{'VIP Room':10,'Executive Room':30,'Pool Site':50,'Banquet Hall':200,'Chamber Hall':500,'Concert Hall':1000}]

choice = input('Please select a venue:')
noPeople = int(input('people:'))

while not validateVenue(choice,venueList,noPeople):
    choice = input('Please select a venue:')
    noPeople = int(input('people:'))

虽然您可以使用while true 和break，但我认为检查while 头部中的条件更优雅。

【讨论】：

【解决方案2】：

它接缝你的意思不是

if choice == '1':
    noPeople <= (int(venueList[0]['VIP Room']))
    return True

但是这个：

if choice == '1' and noPeople <= (int(venueList[0]['VIP Room']))
    return True

比所有作品）

但是！如果你想用类似 Python 的风格编写代码，这样会更好：

    print('''
    [1] vip room(10 person)            [4]Banquet Hall(200 person)
    [2] executive room(30 person)      [5]Chamber Hall(500 person)
    [3] pool site(50 person)           [6]Concert Hall(1000 person)
    ''')
work = {'1':'VIP Room','2':'Executive Room','3':'Pool Site',
        '4':'Banquet Hall','5':'Chamber Hall','6':'Concert Hall'}

def validateVenue(choice,venueList,noPeople):
    if choice in work.keys():
        if noPeople <= (int(venueList[0][work[choice]]):
            return True
        else:
            return False
    else:
        print('Invalid venue, please choose again.')
        return False

venueList = [{'VIP Room':10,'Executive Room':30,'Pool Site':50,'Banquet Hall':200,'Chamber Hall':500,'Concert Hall':1000}]
while True:
    noPeople = int(input('people:'))

    choice = input('Please select a venue:')
    if validateVenue(choice,venueList,noPeople):
        break

它工作得更快！

【讨论】：