MySQL在任何地方查找包含所有字母的单词

Question

使用以下查询

SELECT * FROM words WHERE word REGEXP '(ord)'

• 这将返回像 ford、lord、word 这样的词

如何包含这些字母出现但顺序不同的单词？

• 例如adore、door、random

编辑：

搞定了。

SELECT word, (
    IF(LOCATE('o', word) > 0, 1, 0) + 
    IF(LOCATE('r', word) > 0, 1, 0) +
    IF(LOCATE('z', word) > 0, 1, 0) +
    IF(LOCATE('a', word) > 0, 1, 0) +
    IF(LOCATE('d', word) > 0, 1, 0)) AS chars_present
from words
HAVING chars_present = 5

现在我将如何查询包含字母 r 的单词两次？

Answer 1

在 mysql 中使用正则表达式要求所有三个字符都存在于任何位置会很丑陋，您可能会更好地使用以下内容：

SELECT (
    IF(LOCATE('o', words) > 0, 1, 0) + 
    IF(LOCATE('r', words) > 0, 1, 0) +
    IF(LOCATE('d', words) > 0, 1, 0)) AS chars_present
...
HAVING chars_present = 3

Answer 2

只需对每个字母重复规则即可。

SELECT * FROM words WHERE word REGEXP 'o' AND word REGEXP 'r' AND word REGEXP 'd'

规则出现的顺序无关紧要。

Answer 3

这可能是最快的：

SELECT *
    FROM words
    WHERE LOCATE('o', word)
      AND LOCATE('r', word)
      AND LOCATE('d', word);

mysql> SELECT city, state FROM us
      WHERE locate('o', city) AND locate('r', city) AND locate('d', city)
      LIMIT 11;
+---------------+-------+
| city          | state |
+---------------+-------+
| Irondale      | AL    |
| Oxford        | AL    |
| El Dorado     | AR    |
| Paragould     | AR    |
| Sherwood      | AR    |
| Goodyear      | AZ    |
| Safford       | AZ    |
| Alondra Park  | CA    |
| Anderson      | CA    |
| Arroyo Grande | CA    |
| Atascadero    | CA    |
+---------------+-------+
11 rows in set (0.00 sec)

如果您需要两个r，则对它们的测试将是word REGEXP 'r.*r'：

mysql> SELECT city, state FROM us
    ->           WHERE locate('o', city) AND city REGEXP 'r.*r' AND locate('d', city)
    ->           LIMIT 5;
+--------------------+-------+
| city               | state |
+--------------------+-------+
| Alondra Park       | CA    |
| Arroyo Grande      | CA    |
| Corte Madera       | CA    |
| Desert Hot Springs | CA    |
| Garden Grove       | CA    |
+--------------------+-------+