获取图像高度和宽度 PHP答案

【问题标题】：Get image height and width PHP获取图像高度和宽度 PHP
【发布时间】：2011-11-26 02:47:26
【问题描述】：

您好，我需要即时获取上传图片的高度和宽度。

这是我正在使用的 PHP 函数，但它没有返回任何宽度和高度..

你能帮帮我吗？

list($width, $height, $type, $attr) = getimagesize($_FILES["Artwork"]);
$min_width = "1000";
$min_height = "1000";
if ((($_FILES["Artwork"]["type"] == "image/gif") || ($_FILES["Artwork"]["type"] == "image/jpeg") || ($_FILES["Artwork"]["type"] == "image/jpg")
|| ($_FILES["Artwork"]["type"] == "image/pjpeg")) && ($_FILES["Artwork"]["size"] < 20000000) && ($width > $min_width) && ($height > $min_height) && ($width == $height))
  {


  if ($_FILES["Artwork"]["error"] > 0)
    {
    //echo "Return Code: " . $_FILES["Artwork"]["error"] . "<br />";


   }else{
      move_uploaded_file($_FILES["Artwork"]["tmp_name"],
      $path_image . $imageName);
      header("Location: http://pitchmystuff.co.uk/m/digidist/tracks/".$idAlbum."");
      }



   }else{
    //echo "invalid file";

    echo '<script>
    alert("There was an error uploading your coverart file. Please check the requirements and try again.'.$width.$height.'");
    document.location ="http://pitchmystuff.co.uk/m/digidist/albums/";
    </script>';


    }

【问题讨论】：

getimagesize() 是票。您只是没有使用正确的变量作为参数。应该有这样的错误消息：激活错误报告以查看它。
Get Image Height and Width as integer values? 的可能重复项

标签： php image image-size

【解决方案1】：

应该是

list($width, $height, $type, $attr) = getimagesize($_FILES["Artwork"]['tmp_name']);

见http://www.php.net/manual/en/features.file-upload.post-method.php

【讨论】：

【解决方案2】：

<?php
/*$size = getimagesize("http://heartbeatperformance.com.p9.hostingprod.com/customerphotos/photoes/51HDE3cnl2L.jpg");

list($width, $height) = $size;
echo "width: $width<br />height: $height";*/



$testing = "http://heartbeatperformance.com.p9.hostingprod.com/customerphotos/img/logo.png";
//echo $testing;
list($width, $height, $type, $attr) = getimagesize($testing);
echo "Image width " . $width;
echo "Image height " . $height;



?>

【讨论】：

【解决方案3】：

<?php

$imagedetails = getimagesize($_FILES['Artwork']['tmp_name']);
$width = $imagedetails[0];
$height = $imagedetails[1];

?>

【讨论】：

【解决方案4】：

$DOCS_NAME = $_FILES['DOCS']['name'];
$DOCS_SIZE = getimagesize($_FILES['DOCS']['tmp_name']);
$DOCS      = file_get_contents ($_FILES['DOCS']['tmp_name']);
$FILE_SIZE = $_FILES["DOCS"]["size"];
$FILE_TYPE = $_FILES["DOCS"]["type"];

echo 'Width     = '.$DOCS_SIZE[0]. "<br />";
echo 'Height    = '.$DOCS_SIZE[1]. "<br />";;  
echo '2         = '.$DOCS_SIZE[2]. "<br />";;  
echo '3         = '.$DOCS_SIZE[3]. "<br />";;  
echo 'bits      = '.$DOCS_SIZE['bits']. "<br />";;
echo 'channels  = '.$DOCS_SIZE['channels']. "<br />";;
echo 'mime      = '.$DOCS_SIZE['mime']. "<br />";
echo 'type      = '.$_FILES["DOCS"]["type"]. "<br />";
echo 'size      = '.$_FILES["DOCS"]["size"]. "<br />";

【讨论】：