【发布时间】:2012-04-13 21:51:04
【问题描述】:
我有这个融合表层的实现,我尝试使用带有字母 A-Z 的预定义标记图标来在地图上显示搜索查询的结果(就像原始谷歌地图一样)。
我实现这一点的方法是首先创建一个图层,所有标记都有一个通用图标..
var layer = new google.maps.FusionTablesLayer({
query: {
select: 'Geometry',
from: 0000000
},
map: map,
options: {
suppressInfoWindows: true
},
styles: [{
markerOptions: {
iconName: "measle_white"
}
}]
});
同时,我根据地图的中心位置(地理定位)使用 ST_DISTANCE 排序查询同一张表的 25 个结果,
var queryUrlHead = 'http://www.google.com/fusiontables/api/query?sql=',
queryUrlTail = '&jsonCallback=success',
query = 'SELECT+ID+FROM+0000000+ORDER+BY+ST_DISTANCE(Geometry,LATLNG('+position.coords.latitude+','+position.coords.longitude+'))+LIMIT+25';
var queryurl = queryUrlHead + query + queryUrlTail;
返回的 JSON 对象是一个唯一 ID 的数组,我称之为“ids”。然后我使用一些触发器(zoomchanged)用字母图标重绘最近的 25 个图标(由this 启发)。
google.maps.event.addListener(map, 'zoom_changed', function () {
layer.setOptions({
styles: [{
markerOptions: {
iconName: "measle_white"
}
}, //fallback
{
where: "'ID' = " + ids.table.rows[0][0],
markerOptions: {
iconName: "a_blue"
}
}, {
where: "'ID' = " + ids.table.rows[1][0],
markerOptions: {
iconName: "b_blue"
}
}, {
where: "'ID' = " + ids.table.rows[2][0],
markerOptions: {
iconName: "c_blue"
}
}, {
where: "'ID' = " + ids.table.rows[3][0],
markerOptions: {
iconName: "d_blue"
}
}, {
where: "'ID' = " + ids.table.rows[4][0],
markerOptions: {
iconName: "e_blue"
}
}, {
where: "'ID' = " + ids.table.rows[5][0],
markerOptions: {
iconName: "f_blue"
}
}, {
where: "'ID' = " + ids.table.rows[6][0],
markerOptions: {
iconName: "g_blue"
}
}, {
where: "'ID' = " + ids.table.rows[7][0],
markerOptions: {
iconName: "h_blue"
}
}, {
where: "'ID' = " + ids.table.rows[8][0],
markerOptions: {
iconName: "i_blue"
}
}, {
where: "'ID' = " + ids.table.rows[9][0],
markerOptions: {
iconName: "j_blue"
}
}, {
where: "'ID' = " + ids.table.rows[10][0],
markerOptions: {
iconName: "k_blue"
}
}, {
where: "'ID' = " + ids.table.rows[11][0],
markerOptions: {
iconName: "l_blue"
}
}, {
where: "'ID' = " + ids.table.rows[12][0],
markerOptions: {
iconName: "m_blue"
}
}, {
where: "'ID' = " + ids.table.rows[13][0],
markerOptions: {
iconName: "n_blue"
}
}, {
where: "'ID' = " + ids.table.rows[14][0],
markerOptions: {
iconName: "o_blue"
}
}, {
where: "'ID' = " + ids.table.rows[15][0],
markerOptions: {
iconName: "p_blue"
}
}, {
where: "'ID' = " + ids.table.rows[16][0],
markerOptions: {
iconName: "q_blue"
}
}, {
where: "'ID' = " + ids.table.rows[17][0],
markerOptions: {
iconName: "r_blue"
}
}, {
where: "'ID' = " + ids.table.rows[18][0],
markerOptions: {
iconName: "s_blue"
}
}, {
where: "'ID' = " + ids.table.rows[19][0],
markerOptions: {
iconName: "t_blue"
}
}, {
where: "'ID' = " + ids.table.rows[20][0],
markerOptions: {
iconName: "u_blue"
}
}, {
where: "'ID' = " + ids.table.rows[21][0],
markerOptions: {
iconName: "v_blue"
}
}, {
where: "'ID' = " + ids.table.rows[22][0],
markerOptions: {
iconName: "w_blue"
}
}, {
where: "'ID' = " + ids.table.rows[23][0],
markerOptions: {
iconName: "x_blue"
}
}, {
where: "'ID' = " + ids.table.rows[24][0],
markerOptions: {
iconName: "z_blue"
}
}
]
});
现在,这实际上非常有效,除了前 5 个结果 A-D(后备图标 +1)。这里出了什么问题?我是否达到了一些限制(markerOptions 只需要 5 个值??)还是我弄乱了代码?
旁注:This example 似乎每层有超过 5 个图标,但 Google 做到了,我一个都不懂。
【问题讨论】:
标签: javascript google-maps-api-3 google-fusion-tables