【发布时间】:2015-05-28 07:11:13
【问题描述】:
我已经设法让 Google Maps API 与 mySQL 数据库一起工作。
这和我想要的差不多,但只是注意到缩放栏显示不正确:
http://www.quakerquest.org/meeting_place_search/
有什么建议可以解决这个问题吗?谢谢。
Google API 代码是
<script type="text/javascript">
//<![CDATA[
var map;
var markers = [];
var infoWindow;
var locationSelect;
function load() {
map = new google.maps.Map(document.getElementById("map"), {
center: new google.maps.LatLng(53.3836, -1.4665),
zoom: 6,
mapTypeId: 'roadmap',
mapTypeControlOptions: {style: google.maps.MapTypeControlStyle.DROPDOWN_MENU}
});
infoWindow = new google.maps.InfoWindow();
locationSelect = document.getElementById("locationSelect");
locationSelect.onchange = function() {
var markerNum = locationSelect.options[locationSelect.selectedIndex].value;
if (markerNum != "none"){
google.maps.event.trigger(markers[markerNum], 'click');
}
};
}
function searchLocations() {
var address = document.getElementById("addressInput").value;
var geocoder = new google.maps.Geocoder();
geocoder.geocode({address: address}, function(results, status) {
if (status == google.maps.GeocoderStatus.OK) {
searchLocationsNear(results[0].geometry.location);
} else {
alert(address + ' not found');
}
});
}
function clearLocations() {
infoWindow.close();
for (var i = 0; i < markers.length; i++) {
markers[i].setMap(null);
}
markers.length = 0;
locationSelect.innerHTML = "";
var option = document.createElement("option");
option.value = "none";
option.innerHTML = "Select a meeting house:";
locationSelect.appendChild(option);
}
function searchLocationsNear(center) {
clearLocations();
var radius = document.getElementById('radiusSelect').value;
var searchUrl = 'phpsqlsearch_genxml.php?lat=' + center.lat() + '&lng=' + center.lng() + '&radius=' + radius;
downloadUrl(searchUrl, function(data) {
var xml = parseXml(data);
var markerNodes = xml.documentElement.getElementsByTagName("marker");
var bounds = new google.maps.LatLngBounds();
for (var i = 0; i < markerNodes.length; i++) {
var name = markerNodes[i].getAttribute("Venue");
var nameID = markerNodes[i].getAttribute("VenueID");
var address = markerNodes[i].getAttribute("address");
var distance = parseFloat(markerNodes[i].getAttribute("distance"));
var latlng = new google.maps.LatLng(
parseFloat(markerNodes[i].getAttribute("lat")),
parseFloat(markerNodes[i].getAttribute("lng")));
createOption(name, distance, i);
createMarker(latlng, name, nameID, address);
bounds.extend(latlng);
}
map.fitBounds(bounds);
locationSelect.style.visibility = "visible";
locationSelect.onchange = function() {
var markerNum = locationSelect.options[locationSelect.selectedIndex].value;
google.maps.event.trigger(markers[markerNum], 'click');
};
});
}
function createMarker(latlng, name, nameID, address) {
var html = "<a href='http://www.quakerquest.org/meeting_place_details/index.php?VenueID="+nameID+"'>" + name + "</a> <br/>" + address;
var marker = new google.maps.Marker({
map: map,
position: latlng
});
google.maps.event.addListener(marker, 'click', function() {
infoWindow.setContent(html);
infoWindow.open(map, marker);
});
markers.push(marker);
}
function createOption(name, distance, num) {
var option = document.createElement("option");
option.value = num;
option.innerHTML = name + "(" + distance.toFixed(1) + ")";
locationSelect.appendChild(option);
}
function downloadUrl(url, callback) {
var request = window.ActiveXObject ?
new ActiveXObject('Microsoft.XMLHTTP') :
new XMLHttpRequest;
request.onreadystatechange = function() {
if (request.readyState == 4) {
request.onreadystatechange = doNothing;
callback(request.responseText, request.status);
}
};
request.open('GET', url, true);
request.send(null);
}
function parseXml(str) {
if (window.ActiveXObject) {
var doc = new ActiveXObject('Microsoft.XMLDOM');
doc.loadXML(str);
return doc;
} else if (window.DOMParser) {
return (new DOMParser).parseFromString(str, 'text/xml');
}
}
function doNothing() {}
//]]>
以及显示地图的 HTML:
<div id="map" style="width:100%; height: 40%"></div>
【问题讨论】:
-
您好,可以在这里发布一些相关代码吗? (即你如何初始化谷歌地图)。详情见这里:meta.stackoverflow.com/questions/254428谢谢!
-
现已添加API代码。
-
真的很抱歉发布重复。我确实搜索了“Google Maps API zoom”,但在前几页中没有发现任何明显的东西。所以不幸的是,我无法解释这有什么不同。如果您知道该问题已得到解答,则指向答案的链接可能会有所帮助。