【发布时间】:2017-07-19 03:33:31
【问题描述】:
我有一个 RSA 公钥,看起来像
-----BEGIN PUBLIC KEY-----
MIIBIDANBgkqhkiG9w0BAQEFAAOCAQ0AMIIBCAKCAQEAvm0WYXg6mJc5GOWJ+5jk
htbBOe0gyTlujRER++cvKOxbIdg8So3mV1eASEHxqSnp5lGa8R9Pyxz3iaZpBCBB
vDB7Fbbe5koVTmt+K06o96ki1/4NbHGyRVL/x5fFiVuTVfmk+GZNakH5dXDq0fwv
JyVmUtGYAiMJWPni2hGpAsbyjzLix9UNX5XiYIIrIr55IHtD5u1XNkmYLOdVQ98r
6hez3t2eaE0pP2k+mjRach+2tD93PBZmreHgVZtejumi+ZWLMqpd++AY0AzH0m8E
6sa8JFUAiYZbVtmrcGTCUCkzC2Es1/knSeZ41xki1qD0V3uw/APP8Q+BgbX3SJp0
EQIBAw==
-----END PUBLIC KEY-----
我想在python中找出这个键的模N和指数E是什么?
使用 pycrypto 包我可以像这样加载到密钥:
from Crypto.PublicKey import RSA
# read the public key in:
public_key = RSA.importKey(open('key.pub', 'r').read())
但遵循pycrypto's rsa module 的文档,尚不清楚如何提取较小的组件。我该怎么做?
【问题讨论】:
标签: python cryptography rsa public-key pycrypto