SQL查询的猫鼬等价物是什么

Question

select _id from project where projectName = '***' order by viewCount desc limit 5

我还是 mongoose 的新手，对 SQL 的理解有点中级，这是我的尝试，因为我正在尝试检索排序返回的 ObjectId

ProjectModel.find({id}).sort({viewCount: -1}).limit(5).exec( 
    function(err, projects) {
        ...
    }
);

Answer 1

ProjectModel.find({projectName: '***'}, ["_id"]).sort({viewCount: -1}).limit(5).exec( 
    function(err, projects) {
        ...
    }
);