sqlite3 错误：您没有为绑定 1 提供值

Question

def save():
    global editor
    conn = sqlite3.connect('address_book.db')

    c = conn.cursor()

    recordID = delete_box.get()

    c.execute("""UPDATE addresses SET
                first_name=:first,
                last_name=:last,
                address=:address,
                city=:city,
                state=:state,
                zipcode=:zipcode

                WHERE oid=:oid""",
                {
                'oid': int(recordID),
                'first:': ef_name.get(),
                'last': el_name.get(),
                'address': eaddress.get(),
                'city': ecity.get(),
                'state': estate.get(),
                'zipcode': ezipcode.get()})

    conn.commit()
    conn.close()
    editor.destroy()

文件“C:/Users/Luke/PycharmProjects/GUI/database.py”，第 23 行，保存 c.execute("""更新地址集 sqlite3.ProgrammingError：您没有为绑定 1 提供值。

任何人都可以看到导致此错误的原因吗？我确定我没有在任何地方打错字，并且很困惑这可能是什么原因。

Answer 1

错误是由于多余的冒号造成的。替换

'first:': ef_name.get(), 

与

'first': ef_name.get(),

Answer 2

欢迎来到 StackOverflow！我认为您犯的错误是您使用了参数替代样式（paramstyle），这不是sqlite3 上的默认样式。您正在尝试使用 named 样式而不是默认的 qmark 样式。如果您使用qmark 样式，您的UPDATE 将如下所示：

c.execute(
    'UPDATE addresses SET first_name=?, last_name=?, address=?, city=?, state=?, zipcode=? WHERE old=?', 
    (ef_name.get(), el_name.get(), eaddress.get(), ecity.get(), 
     estate.get(), ezipcode.get(), int(recordID))
)

但是如果你真的想使用named 参数样式，你可以为那个模块设置那个属性。这是一个完整的例子：

import sqlite3

sqlite3.paramstyle = 'named'

parameters = [
    {
        'old': 1,
        'first': "Tony",
        'last': "Starks",
        'address': '10880 Malibu Point',
        'city': 'Malibu',
        'state': 'California',
        'zipcode': '12345-6789'
    },
    {
        'old': 1,
        'first': "Pepper",
        'last': "Potts",
        'address': '10880 Malibu Point',
        'city': 'Malibu',
        'state': 'California',
        'zipcode': '12345-6789'
    }
]


conn = sqlite3.connect('address_book.db')
c = conn.cursor()

c.execute('CREATE TABLE addresses (old, first_name, last_name, address, city, state, zipcode)')
c.execute('INSERT INTO addresses  VALUES (:old, :first, :last, :address, :city, :state, :zipcode)', parameters[0])
conn.commit()

print('After INSERT')
for row in c.execute('SELECT * FROM addresses'):
    print(row)

c.execute('UPDATE addresses SET first_name=:first, last_name=:last, address=:address, city=:city, state=:state, zipcode=:zipcode WHERE old=:old', parameters[1])
conn.commit()

print('After UPDATE')
for row in c.execute('SELECT * FROM addresses'):
    print(row)

conn.close()

Answer 3

为了避免报告为https://bugs.python.org/issue41638 的情况，我正在使用包装器。另请参阅python sqlite insert named parameters or null，了解有关如何存储具有需要映射到不同列的不同键集的字典的更一般问题的解决方案。

def testBindingError(self):
        '''
        test list of Records with incomplete record leading to
        "You did not supply a value for binding 2"
        see https://bugs.python.org/issue41638
        '''
        listOfRecords=[{'name':'Pikachu', 'type':'Electric'},{'name':'Raichu' }]
        for executeMany in [True,False]:
            try:
                self.checkListOfRecords(listOfRecords,'Pokemon','name',executeMany=executeMany)
                self.fail("There should be an exception")
            except Exception as ex:
                if self.debug:
                    print(str(ex))
                self.assertTrue('no value supplied for column' in str(ex)) 

导致：

executeMany：

INSERT INTO Pokemon (name,type) values (:name,:type)
failed: no value supplied for column 'type'

没有executeMany：

INSERT INTO Pokemon (name,type) values (:name,:type)
failed: no value supplied for column 'type'
record  #2={'name': 'Raichu'}

包装代码是：

def store(self,listOfRecords,entityInfo,executeMany=False):
        '''
        store the given list of records based on the given entityInfo
        
        Args:
          
           listOfRecords(list): the list of Dicts to be stored
           entityInfo(EntityInfo): the meta data to be used for storing
        '''
        insertCmd=entityInfo.insertCmd
        try:
            if executeMany:
                self.c.executemany(insertCmd,listOfRecords)
            else:
                index=0
                for record in listOfRecords:
                    index+=1
                    self.c.execute(insertCmd,record)
            self.c.commit()
        except sqlite3.ProgrammingError as pe:
            msg=pe.args[0]
            if "You did not supply a value for binding" in msg:
                columnIndex=int(re.findall(r'\d+',msg)[0])
                columnName=list(entityInfo.typeMap.keys())[columnIndex-1]
                debugInfo=""
                if not executeMany:
                    if self.errorDebug:
                        debugInfo="\nrecord  #%d=%s" % (index,repr(record))
                raise Exception("%s\nfailed: no value supplied for column '%s'%s" % (insertCmd,columnName,debugInfo))
            else:
                raise pe

更多详情见storage/sql.py和tests/testSqlite3.py