【发布时间】:2021-07-11 12:03:49
【问题描述】:
您好,我正在尝试将用户选择的图像保存到文件中,以便稍后将其上传到我的 mySQL 数据库。
所以我有这个代码:
var result = await MediaPicker.PickPhotoAsync(new MediaPickerOptions
{
Title = "Please pick a selfie"
});
var stream = await result.OpenReadAsync();
resultImage.Source = ImageSource.FromStream(() => stream);
string path = Environment.GetFolderPath(Environment.SpecialFolder.Personal);
string filename = Path.Combine(path, "myfile");
using (var streamWriter = new StreamWriter(filename, true))
{
streamWriter.WriteLine(GetImageBytes(stream).ToString());
}
using (var streamReader = new StreamReader(filename))
{
string content = streamReader.ReadToEnd();
System.Diagnostics.Debug.WriteLine(content);
}
这里是 GetImageBytes(..) 函数:
private byte[] GetImageBytes(Stream stream)
{
byte[] ImageBytes;
using (var memoryStream = new System.IO.MemoryStream())
{
stream.CopyTo(memoryStream);
ImageBytes = memoryStream.ToArray();
}
return ImageBytes;
}
代码类型有效,它创建一个文件但不保存图像。相反,它会保存“System.Bytes[]”。它保存对象的名称,而不是对象的内容。
任何帮助将不胜感激。谢谢!
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