在开关情况下，我想根据我的要求打印 nslog？答案

【问题标题】：in switch case i want to print nslog as per my requirement?在开关情况下，我想根据我的要求打印 nslog？
【发布时间】：2017-10-23 12:21:48
【问题描述】：

- (IBAction)calciAction:(id)sender {

        weightBMI=(([_weightinpounds.text floatValue]) * 4.88)/((([_feet.text floatValue])+ ([_inch.text floatValue]/12)) *(([_feet.text floatValue])+ ([_inch.text floatValue]/12)));

    NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
    formatter.numberStyle = NSNumberFormatterDecimalStyle;
    formatter.maximumFractionDigits = 2;
    formatter.roundingMode = NSNumberFormatterRoundUp;

    NSString *numberString = [formatter stringFromNumber:@(weightBMI)];
    NSLog(@"YOUR BMI:%@",numberString);

   // NSLog(@"Print BMI %f",weightBMI);
   // float height = (([_feet.text floatValue]) + ([_inch.text floatValue]));


    if (weightBMI>19) {
        NSLog(@"low weight");
    }
    else if ((weightBMI<=19)||(weightBMI>=24))
    {
        NSLog(@"low normal");
    }
    else if ((weightBMI<=25)||(weightBMI>=29))
    {
        NSLog(@"over weight");
    }



}

如果没有正确打印的块如何写入else

【问题讨论】：

这里面临什么问题？
你的情况是错误的检查这个 if (weightBMI=19)||(weightBMI

标签： ios ios5 ios4 ios-3.x ios3.0

【解决方案1】：

在代码中添加“普通语言”cmets 通常会有所帮助。我假设这是您要测试的内容：

// if weightBMI is LESS THAN 19, weight is low
// if weightBMI is GREATER THAN or EQUAL TO 19, but LESS THAN 25, weight is normal
// if weightBMI is EQUAL TO or GREATER THAN 25, weight is over

if (weightBMI < 19) 
{
    NSLog(@"low weight");
}
else if (weightBMI < 25)
{
    NSLog(@"normal");
}
else
{
    NSLog(@"over weight");
}

【讨论】：

【解决方案2】：

如果您将来使用 swift 编写代码。因为它很短。 :)

 switch weightBMI {
        case Int.min..<20:
            print("low weight")
        case 20..<26:
            print("low normal")
        default:
            print("over weight")

        }

【讨论】：