我想从我的颤振应用程序启动 WhatsApp 应用程序

Question

我在我的项目中使用这个依赖 url_launcher: ^5.4.1 通过我的颤振应用程序启动 whatsapp 但是当我按下按钮启动应用程序时它不起作用但在模拟器上显示无法打开链接的错误消息. 下面给出的是我用来启动whatsapp的函数代码。

import 'package:flutter/material.dart';
import 'package:url_launcher/url_launcher.dart';
import 'dart:io';


void main() => runApp(Wapp());

class Wapp extends StatelessWidget {
  // This widget is the root of your application.
  @override
  Widget build(BuildContext context) {
    return MaterialApp(
      debugShowCheckedModeBanner: false,
      title: 'Flutter Demo',
      theme: ThemeData(
          primarySwatch: Colors.orange,
      ),
      home: MyHomePage(title: 'Flutter Demo Home Page'),
    );
  }
}

class MyHomePage extends StatefulWidget {
  MyHomePage({Key key, this.title}) : super(key: key);

final String title;

  @override
  _MyHomePageState createState() => _MyHomePageState();
}

class _MyHomePageState extends State<MyHomePage> {
 void launchWhatsApp(
    {@required int phone,
    @required String message,
    }) async {
  String url() {
    if (Platform.isAndroid) {
      return "whatsapp://wa.me/$phone:03452121308:/?text=${Uri.parse(message)}";
    } else {
      return "whatsapp://send?   phone=$phone&text=${Uri.parse(message)}";
    }
  }

  if (await canLaunch(url())) {
    await launch(url());
  } else {
    throw 'Could not launch ${url()}';
  }
}


Widget build(BuildContext context){
  return Scaffold(
    appBar: AppBar(
      title: Text("Home"), 
    ),

  body: Center(
    child: RaisedButton(
      
      color: Colors.orange,
      textColor: Colors.black,
      padding: EdgeInsets.symmetric(vertical: 20.0, horizontal: 60.0),
      highlightColor: Colors.green,
      onPressed: () {
        launchWhatsApp(phone: 03452121308, message: 'Hello');
      },
      child: Text("Place Your Order",style: TextStyle(
          
          fontWeight: FontWeight.bold,
          fontSize: 15
          
        )
      )
    )
  )

  );
}

}

Answer 1

我找到了将此代码添加到 android/app/src/main/AndroidManifest.xml 的解决方案

<queries>
<intent>
    <action android:name="android.intent.action.VIEW" />
    <data android:scheme="https" />
</intent>
<intent>
    <action android:name="android.intent.action.DIAL" />
    <data android:scheme="tel" />
</intent>
<intent>
    <action android:name="android.intent.action.SEND" />
    <data android:mimeType="*/*" />
</intent>

Answer 2

 String url() {
      if (Platform.isIOS) {
        return "whatsapp://wa.me/$phone/?text=${Uri.encodeFull(message)}";
      } else {
        return "whatsapp://send?phone=$phone&text=${Uri.encodeFull(message)}";
      }
    }

Answer 3

您的url 中缺少https://。

用您的url() 方法替换下面的代码：

  String url() {
    if (Platform.isAndroid) {
      // add the [https]
      return "https://wa.me/$phone/?text=${Uri.parse(message)}"; // new line
    } else {
      // add the [https]
      return "https://api.whatsapp.com/send?phone=$phone=${Uri.parse(message)}"; // new line
    }
  }