我一直在尝试获取我的设备所连接的 wifi 路由器的 mac 地址。我正在使用 Flutter。
我遇到过几个插件，例如 get_ip、wifi_info_plugin 和 flutter_ip。但要么显示未知，不支持android，不支持ios，要么什么都不显示。
我要做的是让我的应用程序仅在连接到一个特定的wifi路由器时运行。所以基本上，当连接到我以外的其他 wifi 路由器时，应用程序的某些功能将被禁用。
请建议任何其他插件或任何解决方法。
【问题讨论】：
标签： java ios swift flutter dart
您可以使用SystemConfiguration.CaptiveNetwork 框架从支持的接口复制您当前的网络信息。请注意，您需要允许访问您设备的位置并在您的应用功能中启用热点配置和访问 WiFi 信息：
import UIKit
import CoreLocation
import SystemConfiguration.CaptiveNetwork
import NetworkExtension
class ViewController: UIViewController, CLLocationManagerDelegate {
let locationManager = CLLocationManager()
var ssid = ""
var bssid = ""
override func viewDidLoad() {
super.viewDidLoad()
locationManager.delegate = self
}
func locationManager(_ manager: CLLocationManager, didUpdateLocations locations: [CLLocation]) {
if #available(iOS 14.0, *) {
fetchNetworkInfo()
} else {
fetchBSSIDInfo()
}
locationManager.stopUpdatingLocation()
}
@available(iOS, introduced: 4.1.0, deprecated: 14.0)
func fetchBSSIDInfo() {
if let interfaces = CNCopySupportedInterfaces() as? [CFString] {
for interface in interfaces {
if let currentNetworkInfo = CNCopyCurrentNetworkInfo(interface) as? [CFString: Any] {
ssid = currentNetworkInfo[kCNNetworkInfoKeySSID] as? String ?? ""
print("ssid:", ssid)
bssid = currentNetworkInfo[kCNNetworkInfoKeyBSSID] as? String ?? ""
print("bssid:", bssid)
break
}
}
}
}
@available(iOS 14.0, *)
func fetchNetworkInfo() {
NEHotspotNetwork.fetchCurrent { network in
guard let network = network else { return }
print("The SSID for the Wi-Fi network.")
print("ssid:", network.ssid, "\n")
self.ssid = network.ssid
print("The BSSID for the Wi-Fi network.")
print("bssid:", network.bssid, "\n")
self.bssid = network.bssid
print("The recent signal strength for the Wi-Fi network.")
print("signalStrength:", network.signalStrength, "\n")
print("Indicates whether the network is secure")
print("isSecure:", network.isSecure, "\n")
print("Indicates whether the network was joined automatically or was joined explicitly by the user.")
print("didAutoJoin:", network.didAutoJoin, "\n")
print("Indicates whether the network was just joined.")
print("didJustJoin:", network.didJustJoin, "\n")
print("Indicates whether the calling Hotspot Helper is the chosen helper for this network.")
print("isChosenHelper:", network.isChosenHelper, "\n")
}
}
@available(iOS, introduced: 13.2.0, deprecated: 14.0)
func locationManager(_ manager: CLLocationManager,
didChangeAuthorization status: CLAuthorizationStatus) {
didChangeAuthorization(status: status)
}
@available(iOS 14.0, *)
func locationManagerDidChangeAuthorization(_ manager: CLLocationManager) {
didChangeAuthorization(status: manager.authorizationStatus)
}
func didChangeAuthorization(status: CLAuthorizationStatus) {
switch status {
case .notDetermined:
print("The user has not chosen whether the app can use location services.\n")
case .restricted:
print("The app is not authorized to use location services.\n")
case .denied:
print("The user denied the use of location services for the app or they are disabled globally in Settings.\n")
case .authorizedAlways:
print("The user authorized the app to start location services at any time.\n")
case .authorizedWhenInUse:
print("The user authorized the app to start location services while it is in use.\n")
@unknown default: break
}
switch status {
case .notDetermined:
locationManager.requestWhenInUseAuthorization()
case .restricted, .denied:
let alert = UIAlertController(title: "Allow Location Access",
message: "Please turn on Location Services",
preferredStyle: .alert)
alert.addAction(.init(title: "Settings",
style: .default) { _ in
let url = URL(string: UIApplication.openSettingsURLString)!
if UIApplication.shared.canOpenURL(url) {
UIApplication.shared.open(url) { success in
print("Settings opened: \(success)")
}
}
})
alert.addAction(.init(title: "Ok", style: .default))
DispatchQueue.main.async {
self.present(alert, animated: true)
}
case .authorizedWhenInUse, .authorizedAlways:
locationManager.startUpdatingLocation()
@unknown default: break
}
}
}
【讨论】：
谢谢大家，我也在找这个答案。
参考下面提到的代码。 并启用位置权限并启用位置。
class _MyAppState extends State<MyApp> {
WifiInfoWrapper _wifiObject;
@override
void initState() {
super.initState();
initPlatformState();
}
// Platform messages are asynchronous, so we initialize in an async method.
Future<void> initPlatformState() async {
WifiInfoWrapper wifiObject;
// Platform messages may fail, so we use a try/catch PlatformException.
try {
wifiObject = await WifiInfoPlugin.wifiDetails;
} on PlatformException {}
if (!mounted) return;
setState(() {
_wifiObject = wifiObject;
});
}
@override
Widget build(BuildContext context) {
String macAddress = _wifiObject != null ? _wifiObject.bssId.toString() : "mac";
return MaterialApp(
home: Scaffold(
body: Center(
child: Text('Mac of AP - ' + macAddress),
),
),
);
}
}
【讨论】：
看来wifi_info_plugin 是您最好的选择。按照文档，尝试像这样获取 AP MAC：
wifiObject = await WifiInfoPlugin.wifiDetails;
AP_MAC = wifiObject.bssId.toString();
确保AP_MAC != "missing"，并包含在try/catch 中，以防它抛出PlatformException。这可能不适用于 iOS 设备。
【讨论】：
我遇到了同样的问题。我最终使用了位置包。
location: ^3.0.2
bool _serviceEnabled;
_serviceEnabled = await location.serviceEnabled();
if (!_serviceEnabled) {
_serviceEnabled = await location.requestService();
}
【讨论】：