【发布时间】:2019-11-28 13:08:52
【问题描述】:
我使用 socket.io websocket 从后端获取数据,并使用 environmentObject 将其推送到 View(SwiftUI),但问题是我无法获取数据,因为它是 Any 类型
我已经尝试使用“guard var data = socketData else { return }”,但是出现了这个错误: 条件绑定的初始化程序必须具有 Optional 类型,而不是 '[Any]'
import SwiftUI
import SocketIO
import Combine
let manager = SocketManager(socketURL: URL(string: "http://localhost:30000/ios")!, config: [.log(true), .compress])
let socket = manager.defaultSocket
class Socket: BindableObject {
let didChange = PassthroughSubject<Socket,Never>()
var days: String = "Loading..." {
didSet {
didChange.send(self)
}
}
static let sharedInstance = Socket()
init() {
socket.on(clientEvent: .connect) {data, ack in
print("socket connected")
}
socket.on("dailyWeather") {data, ack in
print("just a test")
var data = data as String //Here is the current error
/*do {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
let city = try decoder.decode(day.self, from: data)
self.weatherData.city = city.name
} catch {
print(error)
}*/
self.days = "cur"
}
}
func establishConnection() {
socket.connect()
}
func closeConnection() {
socket.disconnect()
}
}
错误: 无法将类型“[Any]”的值强制转换为类型“String”
【问题讨论】:
-
data是一个与String无关的something 数组。编译器和我们一样无知。 -
如果让 str = data as?字符串 {}
-
它说 if let str = data as? String {} 总是会失败,当我得到数据 [0] 时,我无法在 SwiftUI 文本中显示它
标签: swift websocket socket.io swiftui