我如何区分 actionPerformed 中的两个不同的 JButton？

Question

所以我有我的 JButtons

public static JButton textYes = new JButton("Yes");
public static JButton textNo = new JButton("No");

我的菜单

public static String choiceReroll = "";
public static String menu = "";

还有我的 main() 方法

public static void main(String[] args) throws IOException {
    Greed gui = new Greed();
    gui.launchFrame();
    redirectSystemStreams();

    Container contentPane = f.getContentPane();
    contentPane.add(new Greed());

    Scanner is = new Scanner(System.in);
    System.out.println("Welcome to Greed...");
        do {
    System.out.println("Would you like to play? (yes/no)");
    menu = is.next();
            switch (menu) {
                case "yes":
                    jTextArea1.setText(null);
                    diceOne = 0;
                    diceTwo = 0;
                    diceThree = 0;
                    diceFour = 0;
                    diceFive = 0;
                    System.out.println("Rolling...");
                    Game();

                    break;
                case "no":
                    System.out.println("Goodbye...");
                    System.exit(0);

                    break;
                default:
                    invalidInput();

                    break;
            }
        } while (!"yes".equals(menu) || !"no".equals(menu));
}

然后我有我的 actionListeners

textYes.addActionListener(this);
textNo.addActionListener(this);

如何做到这一点，以便当我单击一个按钮或另一个按钮时，它会在menu = is.next();请求用户输入的地方输入文本

我还希望它只输入文本，具体取决于它单击的按钮。并让它输入文本，无论什么变量要求输入

例如：

menu = is.next();

对比

choiceReroll = is.next();

编辑：更多信息...

我也有我的 performAction() 方法

public void actionPerformed(ActionEvent e) {
    jTextArea1.setText(null);
    if (box1.isSelected()) {
        System.out.println("1 is selected");
        willRerollDiceOne = true;
    }
    else {
        System.out.println("1 not selected");
        willRerollDiceOne = false;
    }
    if (box2.isSelected()) {
        System.out.println("2 is selected");
        willRerollDiceTwo = true;
    }
    else {
        System.out.println("2 not selected");
        willRerollDiceTwo = false;
    }
    if (box3.isSelected()) {
        System.out.println("3 is selected");
        willRerollDiceThree = true;
    }
    else {
        System.out.println("3 not selected");
        willRerollDiceThree = false;
    }
    if (box4.isSelected()) {
        System.out.println("4 is selected");
        willRerollDiceFour = true;
    }
    else {
        System.out.println("4 not selected");
        willRerollDiceFour = false;
    }
    if (box5.isSelected()) {
        System.out.println("5 is selected");
        willRerollDiceFive = true;
    }
    else {
        System.out.println("5 not selected");
        willRerollDiceFive = false;
    }

编辑：我为按钮添加了 actionPerformed，但现在只显示一个

    if (area == "menu") {
        if(e.getSource() == textYes){
            menu = "yes";
        }
        if(e.getSource() == textNo){
            menu = "no";
        }
    }

但是当我点击按钮时，它没有更新，为什么？ 我该如何解决这个问题？

编辑：在 if 语句中添加了“测试”打印输出

    if ("menu".equals(area)) {
            if(e.getSource() == textYes){
                menu = "yes";
                System.out.println("test");
            }
            if(e.getSource() == textNo){
                menu = "no";
            }

每次单击“是”按钮时都会打印“测试”

编辑：这是方法的其余部分：

    public static void main(String[] args) throws IOException {
        Greed gui = new Greed();
        gui.launchFrame();
        redirectSystemStreams();

        Container contentPane = f.getContentPane();
        contentPane.add(new Greed());

        Scanner is = new Scanner(System.in);
        System.out.println("Welcome to Greed...");
            do {
        System.out.println("Would you like to play? (yes/no)");
        area = "menu";
        menu = is.next();
                switch (menu) {
                    case "yes":
                        jTextArea1.setText(null);
                        diceOne = 0;
                        diceTwo = 0;
                        diceThree = 0;
                        diceFour = 0;
                        diceFive = 0;
                        System.out.println("Rolling...");
                        Game();

                        break;
                    case "no":
                        System.out.println("Goodbye...");
                        System.exit(0);

                        break;
                    default:
                        invalidInput();

                        break;
                }
            } while (!"yes".equals(menu) || !"no".equals(menu));
        area = "";
    }

    public static void Game() throws IOException {
        rollDiceOne();
        rollDiceTwo();
        rollDiceThree();
        rollDiceFour();
        rollDiceFive();

        //displayDice();
        displayDiceValues();
        f.validate();
        f.repaint();

        choiceRerollDice();
    }

    public static void choiceRerollDice() {
        Scanner is = new Scanner(System.in);
            do {
                if (!canRerollDiceOne && !canRerollDiceTwo && !canRerollDiceThree && !canRerollDiceFour && !canRerollDiceFive) {
                System.out.println("Sorry, but you may not reroll any more dice...");
                displayDiceValues();
                System.exit(0);
            }
            else {
        System.out.println("Would you like to reroll any (more) dice? (yes/no)");
            choiceReroll = is.next();
                switch (choiceReroll) {
                    case "yes":
                        rerollDice();
                        break;
                    case "no":
                        //endTurn();
                        displayDiceValues();
                        f.repaint();
                        //calculatePlayer1Score();
                        //System.out.println("Thank you for playing!");
                        //System.out.println("Goodbye!");
                        System.exit(0);
                    default:
                        invalidInput();
                    }
                }
            } while (!"yes".equals(choiceReroll) || !"no".equals(choiceReroll));
    }

    public static void rerollDice() {
        Scanner is = new Scanner(System.in);
        System.out.println("Which dice would you like to reroll? (Click the box under the dice!)");
        rollSel = is.next();
        switch (rollSel) {
            case "roll":
            if (willRerollDiceOne) {
                if (canRerollDiceOne) {
                    diceOne = 0;
                    rollDiceOne();
                    canRerollDiceOne = false;
                    box1.setEnabled(false);
                }
                else {
                    System.out.println("error");
                }
            }

            else {
            }
            if (willRerollDiceTwo) {
                if (canRerollDiceTwo) {
                diceTwo = 0;
                rollDiceTwo();
                canRerollDiceTwo = false;
                box2.setEnabled(false);
                }
                else {
                    System.out.println("error");
                }
            }
            else {
            }
            if (willRerollDiceThree) {
                if (canRerollDiceThree) {
                diceThree = 0;
                rollDiceThree();
                canRerollDiceThree = false;
                box3.setEnabled(false);
                }
            }
            else {
            }
            if (willRerollDiceFour) {
                if (canRerollDiceFour) {
                diceFour = 0;
                rollDiceFour();
                canRerollDiceFour = false;
                box4.setEnabled(false);
                }
            }
            else {
            }
            if (willRerollDiceFive) {
                if (canRerollDiceFive) {
                diceFive = 0;
                rollDiceFive();
                canRerollDiceFive = false;
                box5.setEnabled(false);
                }
            }
            else {
            }
            box1.setSelected(false);
            box2.setSelected(false);
            box3.setSelected(false);
            box4.setSelected(false);
            box5.setSelected(false);
            f.validate();
            f.repaint();
                break;
            default:
                System.out.println("Error...");
        }

Answer 1

在您的 actionPerformed 方法中执行以下操作：

public void actionPerformed(ActionEvent e) { 
    if(e.getSource() == textYes){
      //perform action when textYes clicked
    }
    if(e.getSource() == textNo){
      //perform action when textNo clicked
    }
}

而不是这个：

Scanner is = new Scanner(System.in);
        System.out.println("Welcome to Greed...");
            do {
        System.out.println("Would you like to play? (yes/no)");
        area = "menu";
        menu = is.next();
                switch (menu) {
                    case "yes":
                        jTextArea1.setText(null);
                        diceOne = 0;
                        diceTwo = 0;
                        diceThree = 0;
                        diceFour = 0;
                        diceFive = 0;
                        System.out.println("Rolling...");
                        Game();

                        break;
                    case "no":
                        System.out.println("Goodbye...");
                        System.exit(0);

                        break;
                    default:
                        invalidInput();

                        break;
                }
            } while (!"yes".equals(menu) || !"no".equals(menu));
        area = "";

您可以创建一个将输入作为参数的方法。

public void start(String menu){
                switch (menu) {
                    case "yes":
                        jTextArea1.setText(null);
                        diceOne = 0;
                        diceTwo = 0;
                        diceThree = 0;
                        diceFour = 0;
                        diceFive = 0;
                        System.out.println("Rolling...");
                        Game();

                        break;
                    case "no":
                        System.out.println("Goodbye...");
                        System.exit(0);

                        break;
                    default:
                        invalidInput();

                        break;
                }
}

然后在执行的动作中，只做：

if(e.getSource() == textYes){
            start("yes");
        }
        if(e.getSource() == textNo){
            start("no");
        }

Answer 2

如何区分 actionPerformed 中的两个不同 JButton？ 我有我的 actionListeners

textYes.addActionListener(this);
textNo.addActionListener(this);

最简洁的方法是使用单独的侦听器。您可以使用匿名内部类来执行此操作，例如

textYes.addActionListener(new ActionListener() {
    public void actionPerformed(ActionEvent e) { 
        // here you can do any necessary actions for the "Yes" button,
        // like calling a specific method of the outer class which handles the event
    }
});

textNo.addActionListener(new ActionListener() {
    public void actionPerformed(ActionEvent e) { 
        // here you can do any necessary actions for the "No" button,
        // like calling a specific method of the outer class which handles the event
    }
});

如果您仍想只使用一个动作侦听器，ActionEvent 中的getSource() 方法允许您访问事件源，正如@ZouZou 已经提到的那样。

另见How do you add an ActionListener onto a JButton in Java。

Answer 3

从ActionEvent，您可以获得action command。因此，只需 set an action command 到每个按钮即可识别它们。

Answer 4

getSource() 由 EventObject 类指定，ActionEvent 是 (via java.awt.AWTEvent). 的子级，这为您提供了对事件来自的对象的引用

或者使用setActionComman(String command)为每个JButton设置命令，然后使用getActionCommand获取相关操作命令。

String cmd = event.getActionCommand();

Answer 5

为每个字段分配不同的ActionListener。我强烈建议您这样做，并且不要使用ActionListener 扩展具有这些字段的容器并将其传递为this。它保留了封装性，它强制分离关注点，并且它是一个干净、易于理解的代码。

所以，每个按钮都应该像这样添加ActionListener：

textYes.addActionListener(new ActionListener() {
    @Override
    public void actionPerformed(Action event e) {
        //logic
    }
});