提取''之间的字符串

Question

美好的一天，我正在努力寻找代码来解析字符并仅实现''之间的内容。在这种情况下，我有：

Char Character = "'2'; 0x32"

在这里，我只想从字符串中提取 2 并将其保存到另一个变量中。如果有人可以为我提供执行此操作的代码，将不胜感激！

Answer 1

在 C++ 中你可以这样写：

#include <stdio.h>  // for sscanf
int main()
{
  // your string
  const char *text = "'2'; 0x32";

  // your variable
  int variable;

  // a working variable, to be set to the number of characters matched by sscanf
  int used;

  // match the patter on a single quote followed by an integer
  // if that integer is found, its value will be written to `variable`
  // then write the used characters into `used` working variable
  // the result from the function is 1, when the variable was found
  if (sscanf(text, "'%d%n", &variable, &used) != 1)
  {
    // explain to the user that there is a syntax error
    printf("Invalid input: expecting \"^'[0-9]+'(.*)\"");

    // exit with an error
    return 1;
  }

  // confirm that after the integer there is a single quote
  if (text[used] != '\'')
  {
    // explain to the user that there is a syntax error
    printf("An integer was found, but no trailing single quote exists.");

    // exit with an error
    return 2;
  }

  // success
  printf("The integer enclosed in the single quotes is %d", variable);

  // exit without errors
  return 0;
}