在 Yii 中将此查询转换为 CDbCriteria 格式答案

【问题标题】：Convert this query into CDbCriteria format in Yii在 Yii 中将此查询转换为 CDbCriteria 格式
【发布时间】：2015-02-15 01:22:22
【问题描述】：

我仍在研究 Yii 1.xx 中 CDbCriteria 的全部功能 - 我有一个相当复杂的 SQL 查询，我想将其转换为使用 CDbCriteria 格式和模型内的查询（如果这可以通过更复杂的查询。

我最初的尝试..

$criteria = new CDbCriteria;
$criteria->select = array(
    't.classroom_id, title',
    'COALESCE(COUNT(DISTINCT r.redeemed_code_id),0) AS totalRewards',
    'COALESCE(COUNT(DISTINCT ocm.user_id),0) AS totalStudents',
    'COALESCE(SUM(r.points),0) AS totalPoints'
 );

任何人都可以使用以下查询建议解决此问题的最佳方法吗？建议任何建议谢谢..

SELECT
  t.classroom_id,
  title,
  COALESCE ( r.classRewards, 0 ) AS totalRewards,
  COALESCE ( r.classPoints, 0) AS totalPoints,
  COALESCE ( COUNT(DISTINCT ocm.user_id), 0 ) AS totalStudents
 FROM
  organisation_classrooms t
     LEFT JOIN ( select crc.classroom_id,
                        COUNT( DISTINCT crc.redeemed_code_id ) AS classRewards,
                        SUM( crc.points ) as classPoints
                    from classroom_redeemed_codes crc
                       JOIN organisation_classrooms t
                          ON crc.classroom_id = t.classroom_id 
                          AND t.organisation_id = 37383
                    where crc.inactive = 0
                      AND ( crc.date_redeemed >= 1393286400
                       OR crc.date_redeemed = 0 )
                    group by crc.classroom_id ) r
        ON t.classroom_id = r.classroom_id

     LEFT OUTER JOIN organisation_classrooms_myusers ocm
        ON t.classroom_id = ocm.classroom_id
 WHERE
  t.organisation_id = 37383
 GROUP BY title
 ORDER BY t.classroom_id ASC
 LIMIT 10

【问题讨论】：

我认为这样复杂的查询最好不要使用 CDbCriteria。您可以尝试改用 CDbCommandBuilder

标签： php mysql yii yii-components

【解决方案1】：

它不漂亮，但你要求它：D

$criteria = new CDbCriteria();
$criteria->select = '
  t.classroom_id,
  title,
  COALESCE ( r.classRewards, 0 ) AS totalRewards,
  COALESCE ( r.classPoints, 0) AS totalPoints,
  COALESCE ( COUNT(DISTINCT ocm.user_id), 0 ) AS totalStudents';

$criteria->join = '
    LEFT JOIN ( select crc.classroom_id,
                        COUNT( DISTINCT crc.redeemed_code_id ) AS classRewards,
                        SUM( crc.points ) as classPoints
                    from classroom_redeemed_codes crc
                       JOIN organisation_classrooms t
                          ON crc.classroom_id = t.classroom_id 
                          AND t.organisation_id = 37383
                    where crc.inactive = 0
                      AND ( crc.date_redeemed >= 1393286400
                       OR crc.date_redeemed = 0 )
                    group by crc.classroom_id ) r
        ON t.classroom_id = r.classroom_id

     LEFT OUTER JOIN organisation_classrooms_myusers ocm
        ON t.classroom_id = ocm.classroom_id
';

$criteria->group = 'title';
$criteria->order = 't.classroom_id ASC';
$criteria->limit = 10;
$criteria->addCondition('t.organisation_id = :id');
$criteria->params[':id'] = 37383;

然后：

// I will assume that model class name is OrganisationClassrooms
$models = OrganisationClassrooms::model()->findAll($criteria);

// or use it with a dataprovider
$dataProvider= new CActiveDataProvider('OrganisationClassrooms' , array(
  'criteria' => $criteria,
))

【讨论】：

我什至没有时间测试这个......但是，嘿，它的圣诞节，对我来说看起来不错。赏金是你的 :)

【解决方案2】：

我建议您为此创建存储过程，以便您可以轻松处理此查询。例如。 -

$sql = Yii::app()->db->createCommand("CALL sp_getstudentdetails(:organisation_id, :date_redeemed)");
$row = $sql->queryAll(array(':organisation_id' => $organisation_id, ':date_redeemed' => date_redeemed));

【讨论】：