继承 QObject 的类中的方法在调用时被标识为属性，不运行方法

Question

基本上，我有一个我正在开发的项目，它应该是井字游戏的图形游戏，并且从主程序调用一个名为“Game”的类（以及任何方法调用） qml 文件不起作用。返回此错误：

TypeError: Property 'takeTurn' of object [object Object] is not a function

我在这个类中继承了 QObject，并包含了 Q_OBJECT 宏并将该方法标记为 Q_INVOKABLE。

代码编译和链接都很好，这是一个运行时错误。

以下是相关代码以提供帮助：

Game.hpp：

#define GAME_HPP

#include "Board.hpp"
#include <ostream>

#include <QObject>

class Game : public QObject
{
    Q_OBJECT;
    public:
        //...
        Q_INVOKABLE void takeTurn(int x, int y);
        Q_INVOKABLE bool checkWin();

        friend std::ostream& operator<<(std::ostream&, const Game&);
    private:
        char player_;
        int turns_;
        Board board_;
};

std::ostream& operator<<(std::ostream&, const Game&);

#endif // GAME_HPP

游戏.cpp：

#include <iostream>

#include <QObject>
#include <QApplication>

using std::cout;
using std::endl;

//...
void Game::takeTurn(int x, int y)
{
    QWindow* app = QApplication::topLevelWindows()[0];
    cout << app << endl;
    board_.setTile(x, y, player_);
    player_ == 'X' ? player_ = 'O' : player_ = 'X';
    turns_++;
}
//...

main.cpp:

#include "Game.hpp"

#include <iostream>
#include <QGuiApplication>
#include <QQmlApplicationEngine>

using std::cout;
using std::endl;

Q_DECL_EXPORT int main(int argc, char *argv[])
{
    QCoreApplication::setAttribute(Qt::AA_EnableHighDpiScaling);

    QGuiApplication app(argc, argv);
    qmlRegisterType<Game>("com.myself", 1, 0, "Game");
    qmlRegisterType<Board>("com.myself", 1, 0, "Board");

    QQmlApplicationEngine engine;
    const QUrl url(QStringLiteral("qrc:/main.qml"));
    QObject::connect(&engine, &QQmlApplicationEngine::objectCreated,
                     &app, [url](QObject *obj, const QUrl &objUrl) {
        if (!obj && url == objUrl)
            QCoreApplication::exit(-1);
    }, Qt::QueuedConnection);
    engine.load(url);

    return app.exec();
}

main.qml:

import QtQuick.Window 2.12
import com.myself 1.0

Window {
    visible: true
    width: 600
    height: 600
    title: qsTr("TicTacToe")

    Item {
        //...

        MouseArea {
            id: mouseArea1
            anchors.fill: parent
            onClicked: {
                Game.takeTurn(0,0)
            }
        }
    }
//...

}
//...

Answer 1

您已经将Game注册为一个类型，所以您需要做的是创建一个该类型的对象，错误指向该问题：

// ...
Window {
    visible: true
    width: 600
    height: 600
    title: qsTr("TicTacToe")
    Game {
        id: game
    }

    // ...
    Item {
        // ...
        MouseArea {
            id: mouseArea1
            anchors.fill: parent
            onClicked: {
                game.takeTurn(0,0)
            }
       }
    }
    // ...