【发布时间】:2011-08-05 11:08:00
【问题描述】:
根据一些建议,我决定为我的网络应用编写自己的授权过滤器(我没有使用容器管理的安全性,所以我必须这样做)。
这是我的第一个过滤器,所以我对如何实现它有点困惑。 这是我到目前为止所做的:
package filters;
import java.io.IOException;
import javax.servlet.Filter;
import javax.servlet.FilterChain;
import javax.servlet.FilterConfig;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;
import entities.Role;
public class RestrictPageFilter implements Filter {
FilterConfig fc;
public void init(FilterConfig filterConfig) throws ServletException {
// The easiest way to initialize the filter
fc = filterConfig;
}
public void doFilter(ServletRequest request, ServletResponse response,
FilterChain chain) throws IOException, ServletException {
HttpServletRequest req = (HttpServletRequest) request;
HttpServletResponse resp = (HttpServletResponse) response;
HttpSession session = req.getSession(true);
String pageRequested = req.getRequestURL().toString();
Role currentUser = (Role) session.getAttribute("userRole");
//Pages that are allowed with no need to login:
//-faq.xhtml
//-index.jsp
//-login.xhtml
//-main.xhtml
//-registration.xhtml
//NOW pages that are restricted depending on the type of user
//buyoffer.xhtml(Only BUYER)
//sellerpanel.xhtml(Only SELLER)
//adminpanel.xhtml(Only ADMINISTRATOR)
//HOW SHOULD I IMPLEMENT THAT??
if(currentUser != null && currentUser.getType().equals("BUYER")) {
}
if(currentUser != null && currentUser.getType().equals("SELLER")) {
}
if(currentUser != null && currentUser.getType().equals("ADMINISTRATOR")) {
}
}
public void destroy() {
// Not needed
}
}
如你所见,我把 cmets 留在了我卡住的地方。有人可以帮我完成这个过滤器或给我一些伪代码提示我应该如何完成它?
我在网上看到了一些示例,但没有一个根据用户类型进行不同的过滤。
非常感谢您的帮助:)
更新
我创建了一个 xml 文件来帮助我进行过滤(它位于 WEB-INF/classes 内)
<access>
<buyer>
<page>buyoffer.xhtml</page>
<page>faq.xhtml</page>
<page>index.jsp</page>
<page>login.xhtml</page>
<page>main.xhtml</page>
<page>registrationSucceded.xhtml</page>
</buyer>
<seller>
<page>sellerpanel.xhtml</page>
<page>faq.xhtml</page>
<page>index.jsp</page>
<page>login.xhtml</page>
<page>main.xhtml</page>
<page>registrationSucceded.xhtml</page>
</seller>
<administrator>
<page>sellerpanel.xhtml</page>
<page>faq.xhtml</page>
<page>index.jsp</page>
<page>login.xhtml</page>
<page>main.xhtml</page>
<page>registrationSucceded.xhtml</page>
</administrator>
</access>
<!-- THE REGISTRATION PAGES SHOULD NOT BE ACCESSIBLE IF THE USER IS LOGGED IN -->
我从 init() 方法读取文件。()
public class RestrictPageFilter implements Filter {
private FilterConfig fc;
private InputStream in;
public void init(FilterConfig filterConfig) throws ServletException {
// The easiest way to initialize the filter
fc = filterConfig;
//Get the file that contains the allowed pages
in = this.getClass().getResourceAsStream("/allowedpages.xml");
}
public void doFilter(ServletRequest request, ServletResponse response,
FilterChain chain) throws IOException, ServletException {
HttpServletRequest req = (HttpServletRequest) request;
HttpServletResponse resp = (HttpServletResponse) response;
HttpSession session = req.getSession(true);
String pageRequested = req.getRequestURL().toString();
//Get the value of the current logged user
Role currentUser = (Role) session.getAttribute("userRole");
if (currentUser != null) {
}
}
public void destroy() {
// Not needed
}
}
【问题讨论】:
-
所以您的具体问题是“如何使用 Java EE 读取 XML 文件”?
-
是的,这是我很困惑的事情之一。我就该主题提出了一个问题:stackoverflow.com/questions/5663581/… 我决定使用 JAXP 解析器
标签: java jsf jakarta-ee jsf-2 authorization