【发布时间】:2014-02-01 05:53:05
【问题描述】:
我有一个问题要在 dataTable 中显示一些值
这是dataTable的代码
<h:form>
<p:dataTable var="car" value="#{competence.getAllCompetence()}">
<p:column headerText="Model">
<h:outputText value="#{car.idCompetence}" />
</p:column>
</p:dataTable>
这是查询
public List<Object> findAllCompetence() {
// TODO Auto-generated method stub
return getHibernateTemplate().find("select c,pro from Competence as c join c.technologies as pro ");
}
并且消息错误是
Grave: Error Rendering View[/default.xhtml]
java.lang.NumberFormatException: For input string: "idCompetence"
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at javax.el.ArrayELResolver.coerce(ArrayELResolver.java:159)
at javax.el.ArrayELResolver.getValue(ArrayELResolver.java:45)
at com.sun.faces.el.DemuxCompositeELResolver._getValue(DemuxCompositeELResolver.java:173)
at com.sun.faces.el.DemuxCompositeELResolver.getValue(DemuxCompositeELResolver.java:200)
at org.apache.el.parser.AstValue.getValue(AstValue.java:183)
at org.apache.el.ValueExpressionImpl.getValue(ValueExpressionImpl.java:185)
Hibernate: select competence0_.idCompetence as idCompet1_3_0_, technologi1_.idTechnologie as idTechno1_7_1_, competence0_.llibelleCompetence as llibelle2_3_0_, competence0_.description as descript3_3_0_, competence0_.niveauExpert as niveauEx4_3_0_, technologi1_.idCompetence as idCompet2_7_1_, technologi1_.libelleTechnologie as libelleT3_7_1_ from gestioncollaborateur.competence competence0_ inner join gestioncollaborateur.technologie technologi1_ on competence0_.idCompetence=technologi1_.idCompetence
我不知道问题是什么,我认为它与返回对象有关
【问题讨论】:
-
您可以尝试运行正在打印的查询吗?你可能会从中得到线索。
-
我如何运行它!赫里希凯诗
-
嗯,在您的second question 中,您使用了另一个查询。
-
运行您的查询,其中显示 Hibernate : 在您的问题中。使用 SQLDeveloper 或 Toad 直接在您的数据库上运行它。
标签: spring hibernate jsf jakarta-ee hql