【发布时间】:2017-09-05 15:51:47
【问题描述】:
好的,所以我有一个页面,我可以在其中加载我的项目供访问者观看:
@extends('layouts.master')
@section('title', 'Projects')
@section('content')
<div class="container">
<div class="contact-wrapper ">
<h1 class="text-center">Project overview</h1>
@foreach($projects as $project)
<div class="col-md-4 no-padding">
<div class="project-image col-md-12 no-padding">
<a href="{{ route('project.view', $project->id) }}">
<img src="{{ $project->image }}" class="col-md-12 image">
<p class="image-text">
{{ $project->title }}
</p>
</a>
</div>
</div>
@endforeach
</div>
</div>
@stop
但我会收到以下错误:
Route [project.view] not defined. (View: /home/vagrant/Code/test/resources/views/projects.blade.php)
虽然我在我的 web.php 路由文件中定义了它,如下所示
<?php
Auth::routes();
Route::get('/', 'HomeController@welcome');
Route::group(['middleware' => ['web']], function() {
Route::resource('user', 'UserController', ['only' => ['index', 'show']]);
Route::resource('project', 'ProjectController', ['only' => ['index', 'show', 'view']]);
Route::resource('blog', 'BlogController', ['only' => ['index', 'show']]);
Route::resource('review', 'ReviewController', ['only' => ['index', 'show']]);
});
Route::group(['middleware' => ['auth']], function () {
Route::resource('user', 'UserController', ['only' => ['store', 'update', 'destroy', 'create', 'edit', 'search', 'cms']]);
Route::resource('project', 'ProjectController', ['only' => ['store', 'update', 'destroy', 'create', 'edit', 'search', 'cms']]);
Route::resource('blog', 'BlogController', ['only' => ['store', 'update', 'destroy', 'create', 'edit', 'search', 'cms']]);
Route::resource('review', 'ReviewController', ['only' => ['store', 'update', 'destroy','create', 'edit', 'search', 'cms']]);
Route::get('/home', 'HomeController@index');
});
在我的 ProjectController.php 中,我定义了如下所示的函数
public function view($id)
{
$projects = Project::findOrFail($id);
$users = User::all();
$userArray = [];
foreach ($users as $user) {
$userArray[$user->id] = $user->username;
}
return view('project.view', compact('projects', 'userArray'));
}
我已了解资源控制器如何只能处理标准的索引/显示/更新等功能,但我怎样才能正确路由它以便它只是我的来自 ProjectController 的功能?
我在正确的文件夹中有视图,并且我 99% 确定我已正确调用它们。视图的路径是:resources/views/project/view.blade.php
提前致谢!
【问题讨论】:
-
你是对的资源控制器默认路由是 laravel 定义的。我的意思是
show、store等,当你必须在资源控制器中添加更多方法时,你的情况view你必须用Route::get('project-view','ProjectController@view')写一个新的路由类似的东西。
标签: php laravel-5 controller routing