【发布时间】:2013-12-01 23:56:24
【问题描述】:
我正在尝试通过递归 CTE 分解 BOM,但我仍然只获得锚行。但是,我正在尝试使用此 SQL 代码:
With BOMTree_CTE
AS
(
--Anchor
Select
B.BOMID
,B.ITEMID
,B.LINENUM
,B.position
,B.BOMQTY
,B.INVENTDIMID
,0 as 'CurrentLevel'
,BV.BOMID as BVBomId
,BV.ITEMID
FROM BOM B Left Join BomVersion BV On B.ItemID = BV.ItemId
Union All
Select
BB.BOMID
,BB.ITEMID
,BB.LINENUM
,BB.position
,BB.BOMQTY
,BB.INVENTDIMID
,CurrentLevel+1
,CAST('1' as nvarchar(20))
,CAST('2' as nvarchar(20))
From Bom BB Join BOMTree_CTE C On BB.BOMID = C.BVBomId
)
select * from BOMTree_CTE C
我不想通过 X++ 做,我需要通过 SQL!
非常感谢任何帮助!
【问题讨论】:
标签: sql-server common-table-expression recursive-query ax