【发布时间】:2018-06-28 11:36:51
【问题描述】:
我有一个来自数据库的类别列表,如下所示:
[
"Travel",
"Apparel & Clothing",
"Footwear",
"Kids & Children",
"Grocery",
"Food & Beverage",
"Innerwear & Swimwear",
"Hotels",
"Bus Tickets",
"Mobiles & Tablets",
"Personalized Gifts",
"Jewellery & Coins",
"Car & Taxi Rental",
"Pharmacy",
"Watches",
"Bags & Wallets",
"Gifts & Flowers",
"Accessories",
"Games",
"Health",
"Beauty & Personal Care",
"Electronics"
]
我正在尝试从此类别列表创建路线,我不确定如何处理列表中某些类别的路线。
例如:
Apparel & Clothing
Bus Tickets
angular 5 路由系统中的“&”符号和空格如何处理?
【问题讨论】:
-
JavaScript 有一个 unescape() 方法。那应该保留符号/空格等,
-
@rrd unescape() 方法已被弃用。我想按原样使用它。有可能吗?
-
如果你假设你只会得到空格和&符号,你可以更手动地做: string.replace('&', '"').replace(' ', ' ' )
标签: angular routing angular2-routing url-routing angular5