如何编写一个可以在 TypeScript 中实现接口的类

Question

我是 TypeScript 的初学者。我有以下代码

async function sleep(ms: number) {
    return new Promise((resolve, reject) => {
        setTimeout(() => resolve(), ms)
    })
}

async function randomDelay() {
    const randomTime = Math.round(Math.random() * 1000)
    return sleep(randomTime)
}

class ShipmentSearchIndex {
    async updateShipment(id: string, shipmentData: any) {
        const startTime = new Date()
        await randomDelay()
        const endTime = new Date()
        console.log(`update ${id}@${
            startTime.toISOString()
            } finished@${
            endTime.toISOString()
            }`
        )

        return { startTime, endTime }
    }
}

// Implementation needed
interface ShipmentUpdateListenerInterface {
    receiveUpdate(id: string, shipmentData: any)
}

我必须编写一个实现ShipmentUpdateListenerInterface 的类。如何在 TypeScript 中做到这一点？

Answer 1

使用 implements 关键字让你的类实现接口：

class  ShipmentUpdate implements ShipmentUpdateListenerInterface {
    receiveUpdate(id: string, shipmentData: any){
    }
}