通过构造函数访问数据以设置方法

Question

我正在使用 Java，我的代码构建成功，但我没有得到我想要的结果。我正在尝试将主类中用户的数据输入传递给另一个名为 Staff 的类。我猜在运行时我的数据永远不会通过 set 和 get 方法来检查。我怎样才能让它们发挥作用？

主类

     System.out.print("please enter staff ID: ");
     String staffID = in.next();
     System.out.println("please enter staff first name and last name:");
     String Fname = in.next();
     String Lname = in.next();

     Staff staff= new Staff (staffID, Fname, Lname);
                                
     System.out.print(staff.toString());

员工班

public class Staff {
     private String StaffID; 
     private String Fname;
     private String Lname;
     
     Staff (String StaffID, String Fname, String Lname){
              this.StaffID = StaffID;
              this.Fname =  Fname;
              this.Lname =  Lname;
     }
     
     //set & get Staff ID
     public void setStaffID (String StaffID){
         if (this.StaffID.length() <= 7)  { 
              this.StaffID = StaffID;
              }
              else
              System.out.println("ID have to be less than or equal 7 digits");
     } 
     
     public String getStaffID (){
              return this.StaffID;
     }
     
     //set & get First name
     public void setFname(String Fname){
              if (Fname.matches("[a-zA-Z]")){
                       this.Fname =Fname;
              }
             else
                  System.out.print("Name have to contains letters only");
     }
     
     public String getFname(){       
              return this.Fname;
     }

     //set & get Last name
     public void setLname(String Lname){
              if (Fname.matches("[a-zA-Z]")){  
                       this.Lname =Lname;
              }
               else
                  System.out.print("Name have to contains letters only");
     }
     
     public String getLname(){       
              return this.Lname;
     }     
     
              @Override
     public String toString(){
         return "\n\t\tStaff information \nID:  " + this.StaffID + "\nFirst name: " + this.Fname
                 +"\nLast name: " +this.Lname ;      
     } 

Answer 1

你需要改变你的构造函数来使用像这样的设置器

Staff (String StaffID, String Fname, String Lname){
   setStaffID(StaffID);
   setFname(Fname);
   setLname(Lname);
}