【发布时间】:2017-06-09 11:31:44
【问题描述】:
我正在尝试设置按钮的样式,以便在启用按钮而不是鼠标悬停时显示默认图像,当启用按钮并且鼠标悬停时显示不同的图像,并且在禁用时(无论鼠标悬停如何)显示一个第三张图片。
我尝试遵循这个answer,但是当我运行我的程序时,我收到Provide value on 'System.Windows.Baml2006.TypeConverterMarkupExtension' threw an exception.' Line number '47' and line position '45'. 的错误,这相当于下面sn-p 中<--- 标识的行:
<!-- Edit Button using edit.png (pencil) -->
<Style x:Key="PencilEditEnabledButtonStyle" TargetType="{x:Type Button}">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type Button}">
<Border HorizontalAlignment="Center"
VerticalAlignment="Center">
<!-- default image -->
<Image x:Name="ButtonImage"
Source="/myLibrary;component/Resources/edit.png"
Height="20"/>
</Border>
<ControlTemplate.Triggers>
<!-- update image on mouseover -->
<Trigger Property="IsMouseOver" Value="true">
<Setter TargetName="ButtonImage"
Property="Source"
Value="/myLibrary;component/Resources/edit_mouseover.png" />
</Trigger>
<!-- update image when button is disabled -->
<Trigger Property="IsEnabled" Value="true">
<Setter TargetName="ButtonImage" <---
Property="Source"
Value="/myLibrary;component/Resources/edit_disabled.png" />
</Trigger>
</ControlTemplate.Triggers>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
这可能吗?如果可以,我该如何更正Style。
【问题讨论】:
标签: wpf button triggers styles controltemplate