PHP查找两个linux时间之间的差异

Question

我试图找出两个 linux 时代之间的差异。我想显示几个月的差异。我从数据库中获取了一个 Linux 时间并将其与 time(); 进行比较。

$sql_sms_transactions = "SELECT MAX(`sendtime`) FROM `sms_transaction`  where customer_id='$customer_id'";

    $result_sms_transactions = mysql_query($sql_sms_transactions);
    while($row2=mysql_fetch_assoc($result_sms_transactions))
{

    $status = $row2['MAX(`sendtime`)'];

    //print $status;
    $month = date('m', $status); // 1-12
    $year = date('YW', $status);
    //print $month;
    //print $year;

    $current=time();
    $monthcurrent = date('m', $current); // 1-12
    $yearcurrent = date('YW', $current);

    //print $monthcurrent;
    //print $yearcurrent;

}

Answer 1

使用DateTime 和DateInterval 对象，这应该可以工作：

$date1 = new DateTime();
$date1->setTimestamp($timestamp1);

$date2 = new DateTime();
$date2->setTimestamp($timestamp2);

$diff = $date1->diff($date2);
// Result of type DateInterval
echo ($diff->y*12) + $diff->m

根据我对您的代码的理解，您必须事先执行此操作：

$timestamp1 = time();
$timestamp2 = $status;