如何获得两个月/年点之间的每个月数和年份

Question

我正在创建一个函数，您可以在其中给出起始年份、月份和结束年份、月份，该函数将在两个给定点之间打印每个月和年。

我已经创建了一个完美运行的函数，但我认为这不是一个好的做法，可能有更好的方法来做到这一点。现在我正在寻求您的帮助以找到更好的方法。

附：我无法获得完整日期作为输入。只能获取月份和年份。

这是我的代码 -

function get_all_months($monthstart = null, $yearstart = null, $monthend = null, $yearend = null) {
if (($monthstart === null) || ($yearstart === null) || ($monthend === null) || ($yearend === null)) {
    $monthend = date('m');
    $yearend = date('Y');
    if($monthend < 6) {
        $yearstart = $yearend - 1;
        $monthstart = (($monthend - 5) + 12);
    } else {
        $yearstart = $yearend;
        $monthstart = $monthend - 5;
    }
}
$month_array = array();
if ($yearstart > $yearend) {
    for ($m=$monthend; $m<=12; $m++) $month_array[] = array('month' => $m, 'year' => $yearend);
    for ($y=$yearend+1; $y<$yearstart; $y++) for ($m=1; $m<=12; $m++) $month_array[] = array('month' => $m, 'year' => $y);
    for ($m=1; $m<=$monthstart; $m++) $month_array[] = array('month' => $m, 'year' => $yearstart);
} elseif ($yearend > $yearstart) {
    for ($m=$monthstart; $m<=12; $m++) $month_array[] = array('month' => $m, 'year' => $yearstart);
    for ($y=$yearstart+1; $y<$yearend; $y++) for ($m=1; $m<=12; $m++) $month_array[] = array('month' => $m, 'year' => $y);
    for ($m=1; $m<=$monthend; $m++) $month_array[] = array('month' => $m, 'year' => $yearend);
} else {
    for ($m=$monthstart; $m<=$monthend; $m++) $month_array[] = array('month' => $m, 'year' => $yearstart);
}
return $month_array;
}

编辑：根据 Nigel Ren 的回答，这是我能想到的最佳方式 -

 function get_all_months($monthstart = null, $yearstart = null, $monthend = null, $yearend = null) {

if (($monthstart === null) || ($yearstart === null) || ($monthend === null) || ($yearend === null)) {
    $monthend = date('m');
    $yearend = date('Y');
    if($monthend < 6) {
        $yearstart = $yearend - 1;
        $monthstart = (($monthend - 5) + 12);
    } else {
        $yearstart = $yearend;
        $monthstart = $monthend - 5;
    }
}

$output = [];

if ($yearstart > $yearend) {
    $time   = strtotime($yearend."-".$monthend);
    $last   = date('m-Y', strtotime($yearstart."-".$monthstart));
} else {
    $time   = strtotime($yearstart."-".$monthstart);
    $last   = date('m-Y', strtotime($yearend."-".$monthend));
}
do {
        $cur_month_year = date('m-Y', $time);
        $month = date('m', $time);
        $year = date('Y', $time);
        $output[] =  array('month'=>$month,'year'=>$year);
        $time = strtotime('+1 month', $time);
    }
    while ($cur_month_year != $last);
    return $output;
}

Answer 1

使用DateTime类和DateInterval，可以创建指定范围的DateTime对象generator：

<?php

function get_all_months(int $monthstart, int $yearstart, int $monthend, int $yearend) {
        $onemonth = new DateInterval('P1M'); // one month interval
        $timeperiod = new DatePeriod(
                DateTime::createFromFormat('Y-m', "{$yearstart}-{$monthstart}"),
                $onemonth,
                DateTime::createFromFormat('Y-m', "{$yearend}-{$monthend}")->add($onemonth)
        );
        foreach ($timeperiod as $pos) {
                yield clone $pos;
        }
}

foreach (get_all_months(12, 2009, 1, 2020) as $month) {
        echo "{$month->format('Y-m')}\n";
}

DateTime 应该比纯字符串或数字数组更灵活（请参阅DateTime::format 了解更多使用选项）。

---

注意：受@keidakida 启发，更新了我的答案。

Answer 2

您可以使用用于这些目的的 PHP 的 DateInterval 类。试试这个代码

<?php
function getMonthsFromRange($start, $end, $format = 'M Y')
{

    $array = array();

    // Since you wanted 1 month it is Period = 1 Month
    $interval = new DateInterval('P1M');

    $realEnd = new DateTime($end);
    $realEnd->add($interval);

    $period = new DatePeriod(new DateTime($start), $interval, $realEnd);

    // Use loop to store date into array 
    foreach ($period as $date)
        $array[] = $date->format($format);

    // Return the array elements 
    return $array;
}

// Function call with passing the start date and end date 
$months = getMonthsFromRange('2010-10', '2011-11');

print_r($months);

它的输出是：

Array ( [0] => Oct 2010 [1] => Nov 2010 [2] => Dec 2010 [3] => Jan 2011 [4] => Feb 2011 [5] => Mar 2011 [6] => Apr 2011 [7] => May 2011 [8] => Jun 2011 [9] => Jul 2011 [10] => Aug 2011 [11] => Sep 2011 [12] => Oct 2011 [13] => Nov 2011 )

Answer 3

根据答案here，只需将开始日期添加1个月，直到您到达结束日期...

function get_all_months($monthstart = null, $yearstart = null, $monthend = null, $yearend = null) {
    $output = [];
    $time   = strtotime($yearstart."-".$monthstart);
    $last   = date('m-Y', strtotime($yearend."-".$monthend));
    do {
        $month = date('m-Y', $time);
        $output[] =  $month;
        $time = strtotime('+1 month', $time);
    }
    while ($month != $last);
    return $output;
}

所以

print_r(get_all_months(4,2008,2,2010));

给...

Array
(
    [0] => 04-2008
    [1] => 05-2008
    [2] => 06-2008
    [3] => 07-2008
    [4] => 08-2008
    [5] => 09-2008
    [6] => 10-2008
    [7] => 11-2008
    [8] => 12-2008
    [9] => 01-2009
    [10] => 02-2009
    [11] => 03-2009
    [12] => 04-2009
    [13] => 05-2009
    [14] => 06-2009
    [15] => 07-2009
    [16] => 08-2009
    [17] => 09-2009
    [18] => 10-2009
    [19] => 11-2009
    [20] => 12-2009
    [21] => 01-2010
    [22] => 02-2010
)

Answer 4

如果我理解正确 - 你得到的月份是一个数字，年份是一个数字，例如 6 和 1997。如果我们假设开始年份总是小于结束年份，我建议这样做。

function distanceBetweenDates(int $sm, int $sy, int $em, int $ey) {
    $monthsBetweenYears = ($ey - $sy + 1) * 12;
    $distanceBetweenMonths = $monthsBetweenYears - $sm - (12 - $em);
    
    $startMonth = $sm + 1;
    $startYear = $sy;
    
    while ($distanceBetweenMonths > 0) {
        if ($startMonth <= 12) {
            echo $startMonth . ' - ' . $startYear;
        } else {
            $startMonth = 1;
            $startYear++;
            echo $startMonth . ' - ' . $startYear;
        }
        echo "\n";
        $startMonth++;
        $distanceBetweenMonths--;
    }
}

您可能需要查看的唯一内容是计算中是否包含或排除给定月份。

这里唯一缺少的是验证，因为如果你在方法中使用类型，它可以被“跳过”。

Answer 5

您可能正在寻找这样的东西：

function get_all_months($monthstart = null, $yearstart = null, $monthend = null, $yearend = null) {
    $month_array = [];
    if ($yearstart == $yearend)
        for ($m=$monthstart; $m<=$monthend; $m++) $month_array[] = array('month' => $m, 'year' => $yearstart);
    else {
        for ($m=$monthstart; $m<=12; $m++) $month_array[] = array('month' => $m, 'year' => $yearstart);
        for ($y=$yearstart+1; $y<$yearend; $y++) for ($m=1; $m<=12; $m++) $month_array[] = array('month' => $m, 'year' => $y);
        for ($m=1; $m<=$monthend; $m++) $month_array[] = array('month' => $m, 'year' => $yearend);
    }
    return $month_array;
}