时间一个while循环python

Question

我正在尝试在一个while循环中计时一个while循环，执行它所花费的总时间，并记录它每次循环所花费的时间。如果可能的话，我需要一种方法来使用我的代码来实现这一点，或者对我可能还不知道的不同概念持开放态度。

import random
import time
import sys

def main():


    looperCPU = 500
    start = time.time()
    while (looperCPU != 0):
        #start = time.time()

        #this is the computation for 3 secs
        time.sleep(3)
        random_number = random.randint(0,1000)

        #Send to printer for processing
        #.75 secs to 4.75 secs to generate a pause before printing
        secondsPause = random.uniform(.75,4.75)


        #This is the printer function
        printerLooper = True
        while printerLooper == True :
            print("Sleeping for ", secondsPause, " seconds")
            print(random_number)
            printerLooper = False


        #
        print("total time taken this loop: ", time.time() - start)
        looperCPU -= 1    



main()

循环将打印一个时间，但我很确定它没有考虑嵌套的 while 循环睡眠时间。如何让 python 为两个 while 循环计时，它需要执行的每个循环（在本例中为 500）？

Answer 1

当您在初始循环之外设置 start 时，您保证您得到的 while 循环执行时间不正确。这就像说：

program_starts = time.time()
while(True):
    now = time.time()
    print("It has been {0} seconds since the loop started".format(now - program_starts))

这是因为开始时间在整个执行时间内保持不变，而结束时间随着时间的推移而稳步增加。 通过将开始时间放在循环中，您可以确保您的开始时间也随着程序运行而增加。

while (looperCPU != 0):
    start_time = time.time()
    # Do some stuff
    while printerLooper == True :
        print("Sleeping for ", secondsPause, " seconds")
        print(random_number)
        printerLooper = False
    end_time = time.time()

    print("total time taken this loop: ", end_time - start_time)

Answer 2

在 python 中，您可以查看此文档https://docs.python.org/2/library/timeit.html
Stackoverflow 示例：How to use timeit module

import timeit
timeit.timeit('"-".join(str(n) for n in range(100))', number=10000)

在 Jupyter 笔记本中，

%%timeit -n 100
import pandas as pd
s = pd.Series([101.00, 121.00])
summary = 0
for item in s:
    summary+=item

Answer 3

正确的想法，但是您对计时功能的位置有点偏离，我在这里更正了：

import random
import time import sys

def main():

    looperCPU = 500
    start = time.time()
    while (looperCPU != 0):
       #this is the computation for 3 secs
       time.sleep(3)
       random_number = random.randint(0,1000)

       #Send to printer for processing
       #.75 secs to 4.75 secs to generate a pause before printing
       secondsPause = random.uniform(.75,4.75)


       #This is the printer function
       printerLooper = True
       myStart = time.time()
       while printerLooper == True :
          print("Sleeping for ", secondsPause, " seconds")
          print(random_number)
          printerLooper = False
          print("total time taken this loop: ", time.time() - myStart)    

       looperCPU -= 1    
main()

Answer 4

你可以使用这个 pytictoc。使用 pip 或 conda 安装。阅读pytictoc 上的文档。它像 matlabs tic toc 一样工作。基本上只是用tic开始计时器并以toc结束。您可以直接打印或将其存储在新变量中。

from pytictoc import TicToc
def main()
    t = TicToc()  # create instance of class
    start_time= t.tic() #start timer
    while ():  


    #end of while loop

    end_time = t.toc()
    print("end_time", end_time)