【发布时间】:2019-11-14 21:04:03
【问题描述】:
我有一个名为 SuggestiveInput 的父组件,它有一个名为 VueSimpleSuggest 的子组件。我在测试中得到了子组件的存根,而不是它的内容。
所以 SuggestiveInput 组件是这样的:
<template >
<div class="suggestive-input">
<vue-simple-suggest ...>
</vue-simple-suggest>
</div>
</template>
<script>
import VueSimpleSuggest from "vue-simple-suggest";
import "vue-simple-suggest/dist/styles.css";
export default {
name: "suggestive-input",
props: {
...
},
components: {
VueSimpleSuggest
},
...
还有我的测试文件:
import chai from "chai";
import { createLocalVue, shallowMount } from "@vue/test-utils";
import SuggestiveInput from "@/components/input/SuggestiveInput";
import * as VueTestUtils from "@vue/test-utils";
const expect = chai.expect;
describe("SuggestiveInput", function() {
let wrapper;
const localVue = createLocalVue();
beforeEach(function() {
wrapper = shallowMount(SuggestiveInput, {
localVue,
propsData: {
suggestionList: ["Client One", "Client Two"],
value: ""
}
});
});
it("shows input element with Bootstrap style", function() {
expect(wrapper.html()).contains("input.form-control").to.be.true;
});
});
@vue/test-utils 版本 ^1.0.0-beta.20
vue版本^2.5.19
我得到以下输出:
AssertionError: expected '<div data-v-6aad8d64="" class="suggestive-input"><vue-simple-suggest-stub data-v-6aad8d64=""></vue-simple-suggest-stub></div>' to include 'input.form-control'
它渲染子组件的存根。如何渲染子组件以获得父组件的纯 HTML?
【问题讨论】:
标签: vue.js vue-component vue-test-utils