如何在 Java 中忽略 XML 文件的父节点

Question

这是我的 XML 文件

<?xml version='1.0' encoding='UTF-8' standalone='yes' ?>
<hierarchy rotation="0">
    <node class="A">
        <node class="B"/>
        <node class="C"/>
        <node class="D"/>
    </node>
</hierarchy>

谁能告诉我java代码忽略class="A"的节点？我只想要以/> 结尾的子节点并读取它们的属性值。我在java中使用DocumentBuilderFactory类来实现上述场景。

Answer 1

这样就可以了：

public static void main(String[] args) throws ParserConfigurationException, IOException, SAXException {
    final String xmlString = "<?xml version='1.0' encoding='UTF-8' standalone='yes' ?>"
    + "<hierarchy rotation=\"0\">"
    + "<node class=\"A\">"
    + "<node class=\"B\"/>"
    + "<node class=\"C\"/>"
    + "<node class=\"D\"/>"
    + "</node>"
    + "</hierarchy>";

    final DocumentBuilder documentBuilder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
    final InputSource inputSource = new InputSource(new StringReader(xmlString));
    final Document document = documentBuilder.parse(inputSource);
    final NodeList childNodes = document.getFirstChild().getFirstChild().getChildNodes();

    for (int i = 0; i < childNodes.getLength(); i++) {
        final Node childNode = childNodes.item(i);
        System.out.println("childNode[" + i + "].getAttributes(): " + toStringAttributes(childNode));
    }
}

private static String toStringAttributes(Node childNode) {
    String attributesString = "[";
    final NamedNodeMap attributes = childNode.getAttributes();

    for (int i = 0; i < attributes.getLength(); i++) {
        final Node node = attributes.item(i);
        attributesString += node.getNodeName();
        attributesString += "=";
        attributesString += "\"" + node.getNodeValue() + "\"";
        if (i < attributes.getLength() - 1) {
            attributesString += ",";
        }
    }
    attributesString += "]";
    return attributesString;
}