直接发布/草稿帖子的 Wordpress 前端表单答案

【问题标题】：Wordpress Front End Form to Publish/Draft Posts directly直接发布/草稿帖子的 Wordpress 前端表单
【发布时间】：2012-07-03 13:33:06
【问题描述】：

我有一个 Wordpress 前端表单，可以直接从我的主题发布/起草帖子：-

<?php
if( 'POST' == $_SERVER['REQUEST_METHOD'] && !empty( $_POST['action'] ) &&  $_POST['action'] == "new_post") {

    // Do some minor form validation to make sure there is content
    $title = $_POST["title"];
    if(!empty($_POST['middle'])) {
    $description = 'a sentence ' . $_POST['middle'] . ' with something in the MIDDLE. a sentence ' . $_POST['end'] . ' with something in the END.';
    }
    $tags = $_POST["tags"];
    $post_cat = $_POST['cat'];

    // ADD THE FORM INPUT TO $new_post ARRAY
    $new_post = array(
    'post_title'    =>  $title,
    'post_content'  =>  $description,
    'post_category' =>  $post_cat,  // Usable for custom taxonomies too
    'tags_input'    =>  $tags,
    'post_status'   =>  'draft',           // Choose: publish, preview, future, draft, etc.
    'post_type' =>  'post',  //'post',page' or use a custom post type if you want to
    );

    //SAVE THE POST
    $pid = wp_insert_post($new_post);

    //REDIRECT TO THE NEW POST ON SAVE
    $link = get_permalink( $pid );
    wp_redirect( '/post-submitted-draft' );

} // END THE IF STATEMENT THAT STARTED THE WHOLE FORM

//POST THE POST YO
do_action('wp_insert_post', 'wp_insert_post');

?>

我有一个简单的 php 表单，它具有以下功能：-

<?php
if(!empty($_POST['middle'])) {
   echo "a sentence".$_POST['middle']." with something in the MIDDLE.";
}

if(!empty($_POST['end'])) {
   echo "a sentence".$_POST['end']." with something in the END.";
}
?>

我想将它包含在表单中，我使用以下方法完成了它：-

if(!empty($_POST['middle'])) {
$description = 'a sentence ' . $_POST['middle'] . ' with something in the MIDDLE. a sentence ' . $_POST['end'] . ' with something in the END.';

但是如果'middle'的字段为空，它将忽略$description的整个值，如果'middle'的字段为空，我希望它只忽略第一句并显示具有该字段的第二句“结束”即

'a sentence ' . $_POST['end'] . ' with something in the END.';

如何让它像这样工作？

【问题讨论】：

标签： php forms wordpress frontend

【解决方案1】：

遵循下面的方法将使整个事情变得更好，更有意义。基本上，将描述变量设置为第一句，如果存在则添加第二位。

if(!empty($_POST['middle'])) {
   $description = "a sentence".$_POST['middle']." with something in the MIDDLE.";
}

if(!empty($_POST['end'])) {
   $description .= "a sentence".$_POST['end']." with something in the END.";
}

if(isset($description)) {
// do something with description
}

另外，根据你的用途考虑转义字符串。

【讨论】：

如果我有一个“开始”字段作为开头的句子，并且它是必填字段，所以用户必须填写它？我应该在上面的代码之前以以下简单的方式添加它吗？ $description = "a sentence".$_POST['start']." with something in the START.";
感谢您的回答，请您看看这个与php和MySQL有关的问题...stackoverflow.com/questions/11282461/…
你也能说出来吗？ stackoverflow.com/questions/11333589/…

【解决方案2】：

改变：

if(!empty($_POST['middle'])) {
$description = 'a sentence ' . $_POST['middle'] . ' with something in the MIDDLE. a sentence ' . $_POST['end'] . ' with something in the END.';

到：

$description = (!empty($_POST['middle']))? 'a sentence ' . $_POST['middle'] . ' with something in the MIDDLE.': '' ;
$description .= (!empty($_POST['end']))? 'a sentence ' . $_POST['end'] . ' with something in the END.': '' ;

【讨论】：