如何对json对象进行排序？答案

【问题标题】：how to sort a json object?如何对json对象进行排序？
【发布时间】：2013-07-08 17:46:38
【问题描述】：

我有一个 json 对象。对象如下所示

{"route":[
{"match":"true","column":"10","fare":"500.0","source":"false","length":"1","name":"41","row":"4","width":"1","zIndex":"0"},
{"match":"true","column":"9","fare":"500.0","source":"false","length":"1","name":"37","row":"3","width":"1","zIndex":"0"},
{"match":"true","column":"8","fare":"500.0","source":"false","length":"1","name":"33","row":"2","width":"1","zIndex":"0"},
{"match":"true","column":"7","fare":"500.0","source":"false","length":"1","name":"29","row":"1","width":"1","zIndex":"0"}}
{"match":"true","column":"6","fare":"500.0","source":"false","length":"1","name":"29","row":"0","width":"1","zIndex":"0"}}

我想根据行和列按升序对该对象进行排序。就像我希望得到的对象如下所示

{"route":[
{"match":"true","column":"6","fare":"500.0","source":"false","length":"1","name":"41","row":"0","width":"1","zIndex":"0"},
{"match":"true","column":"7","fare":"500.0","source":"false","length":"1","name":"37","row":"1","width":"1","zIndex":"0"},
{"match":"true","column":"8","fare":"500.0","source":"false","length":"1","name":"33","row":"2","width":"1","zIndex":"0"},
{"match":"true","column":"9","fare":"500.0","source":"false","length":"1","name":"29","row":"3","width":"1","zIndex":"0"}}
{"match":"true","column":"10","fare":"500.0","source":"false","length":"1","name":"29","row":"4","width":"1","zIndex":"0"}}

有人可以帮我解决这个问题吗？

【问题讨论】：

你看过这个stackoverflow.com/questions/4222690/…了吗？
没有“json 对象”这样的东西。有json字符串。可以解码为原生对象。
看看[].sort。传递一个函数来比较obj.route 数组中每个元素的column 值。文档中有一个对对象数组进行排序的示例。
请参考stackoverflow.com/questions/979256/…
@MarcB 你明白当 OP 说“json object”时，它似乎是一种有用的措辞。我讨厌有人说“我想对 json 进行排序”而你不知道他们的意思。

标签： jquery json

【解决方案1】：

给定提供的对象：

var obj = {
    "route" : [
        {"match":"true","column":"10","fare":"500.0","source":"false","length":"1","name":"41","row":"4","width":"1","zIndex":"0"},
        {"match":"true","column":"9","fare":"500.0","source":"false","length":"1","name":"37","row":"3","width":"1","zIndex":"0"},
        {"match":"true","column":"8","fare":"500.0","source":"false","length":"1","name":"33","row":"2","width":"1","zIndex":"0"},
        {"match":"true","column":"7","fare":"500.0","source":"false","length":"1","name":"29","row":"1","width":"1","zIndex":"0"},
        {"match":"true","column":"6","fare":"500.0","source":"false","length":"1","name":"29","row":"0","width":"1","zIndex":"0"}
    ]
};

你需要在数组上实现一个排序函数，如下所示：

如果列优先于行，则首先检查列的值。如果相等，则检查该行的值。

obj.route.sort(function(a, b) {
    if (a.column == b.column) {
        return a.row == b.row ? 0 : +a.row > +b.row ? 1 : -1;
    }

    return +a.column > +b.column ? 1 : -1;
});

如果行优先于列：

obj.route.sort(function(a, b) {
    if (a.row == b.row) {
        return a.column == b.column ? 0 : +a.column > +b.column ? 1 : -1;
    }

    return +a.row > +b.row ? 1 : -1;
});

FIDDLE DEMO

【讨论】：

@crush 您在引用之前放置的那些加号“+”的目的是什么？（例如+a.row、+b.row）提前致谢。
@KiriSakow 它们是将值转换为数字的一元运算符（如果它最初是字符串）。

【解决方案2】：

var o = {"route":[
{"match":"true","column":"10","fare":"500.0","source":"false","length":"1","name":"41","row":"4","width":"1","zIndex":"0"},
{"match":"true","column":"9","fare":"500.0","source":"false","length":"1","name":"37","row":"3","width":"1","zIndex":"0"},
{"match":"true","column":"8","fare":"500.0","source":"false","length":"1","name":"33","row":"2","width":"1","zIndex":"0"},
{"match":"true","column":"7","fare":"500.0","source":"false","length":"1","name":"29","row":"1","width":"1","zIndex":"0"},
{"match":"true","column":"6","fare":"500.0","source":"false","length":"1","name":"29","row":"0","width":"1","zIndex":"0"}]};

var r = o.route;
// sort
var sorted = r.sort(function (a, b) {
    a = parseInt(a.column, 10);
    b = parseInt(b.column, 10);
    return a < b ? -1 : a > b ? 1 : 0;
});
console.log(sorted);

【讨论】：

感谢这对我来说非常有用:)