Javascript + Discord：对对象进行排序并获得前3名

Question

我正在尝试对不和谐机器人进行排序以显示前 3 名成员。但是我不断收到错误：

JavaScript 错误：未捕获的类型错误：guildStats.slice

这是我尝试过的：

var guildStats = {
  '1234567': {
    xp: 95,
    level: 0,
    last_message: 1631181685724,
    invited: {},
    invited_by: 0
  },
  '0987654': {
    xp: 13,
    level: 0,
    last_message: 1631181527799,
    invited: {},
    invited_by: 0
  },
  '243562345': {
    xp: 18,
    level: 0,
    last_message: 1631181537020,
    invited: {},
    invited_by: 0
  },
  '76533465': {
    xp: 14,
    level: 0,
    last_message: 1631181536875,
    invited: {},
    invited_by: 0
  },
  '34667634567': {
    xp: 8,
    level: 0,
    last_message: 1631181659142,
    invited: {},
    invited_by: 0
  },
  '346534': {
    xp: 98,
    level: 0,
    last_message: 1631181638743,
    invited: {},
    invited_by: 0
  },
  '34343677677886': {
    xp: -63,
    level: 0,
    last_message: 1631181584314,
    invited: {},
    invited_by: 0
  },
  '987654345676543': {
    xp: 20,
    level: 0,
    last_message: 1631181589153,
    invited: {},
    invited_by: 0
  },
  '75634576786588': {
    xp: -140,
    level: 0,
    last_message: 1631181593304,
    invited: {},
    invited_by: 0
  },
  '34343434556566': {
    xp: 43,
    level: 0,
    last_message: 1631181663340,
    invited: {},
    invited_by: 0
  }
};


var byXP = guildStats.slice(0);
byXP.sort(function(a,b) {
    return a.xp - b.xp;
});

document.write(byXP);

我要输出的是

The top 3 members by XP are: 
1. 346534
2. 1234567
3. 34343434556566

我知道我在某个地方搞砸了。

如何按子对象键 xp 的值对guildStats 中的所有对象进行排序

感谢您的帮助。

Answer 1

您可以使用Object.fromEntries() 将您的对象转换为 [key,value] 对的数组。

然后我们可以对 xp 进行排序并使用 Array.slice() 返回前三个条目。

var guildStats = { '1234567': { xp: 95, level: 0, last_message: 1631181685724, invited: {}, invited_by: 0 }, '0987654': { xp: 13, level: 0, last_message: 1631181527799, invited: {}, invited_by: 0 }, '243562345': { xp: 18, level: 0, last_message: 1631181537020, invited: {}, invited_by: 0 }, '76533465': { xp: 14, level: 0, last_message: 1631181536875, invited: {}, invited_by: 0 }, '34667634567': { xp: 8, level: 0, last_message: 1631181659142, invited: {}, invited_by: 0 }, '346534': { xp: 98, level: 0, last_message: 1631181638743, invited: {}, invited_by: 0 }, '34343677677886': { xp: -63, level: 0, last_message: 1631181584314, invited: {}, invited_by: 0 }, '987654345676543': { xp: 20, level: 0, last_message: 1631181589153, invited: {}, invited_by: 0 }, '75634576786588': { xp: -140, level: 0, last_message: 1631181593304, invited: {}, invited_by: 0 }, '34343434556566': { xp: 43, level: 0, last_message: 1631181663340, invited: {}, invited_by: 0 } }; 

var byXP = Object.entries(guildStats);
byXP.sort(function([keya,valuea],[keyb,valueb]) {
    return valueb.xp - valuea.xp;
});

console.log('The top 3 members by XP are:');
byXP.slice(0,3).forEach(([key, member],idx) => console.log(`${idx+1}. ${key}, xp: ${member.xp}`));