如何根据javascript中的类型将嵌套数组对象更改为对象答案

【问题标题】：How to change the nested array object to object depending on type in javascript如何根据javascript中的类型将嵌套数组对象更改为对象
【发布时间】：2020-12-20 03:58:12
【问题描述】：

我想知道如何根据 javascript 中的键将嵌套数组对象更改为对象

我有对象obj1 和obj2，根据item 的键类型更改对象。


function changeObj(obj){
  let result =  obj.reduce(function (acc, item) {
      if(item.items.trim() !== "" && item.key.trim() !== ""){
        acc[item.key] = item.items
        return acc
      }
        return acc
    }, {});
  return result;
}
let result = this.changeObj(obj2)
var obj1 = [
 { id:0, items:["SG","AU"], count: 2, key:"countries"},
 { id:1, items:["finance"], count: 3 key:"info"} 
]

var obj2 = [
  { id:0, items: "SG", key: "country"},
  { id:1, items: "details", key: "info"}
]

Expected Output:

// if items key is array
{
  fields: {
    countries: ["SG","AU",2],
    info: ["finance",3]
  }
}

//if items key is string

{
  fields: {
    country: "SG",
    info: "details"
  }
}

【问题讨论】：

那么你到底是哪里出了问题？
@charlietfl 感谢回复，如果项目键是数组，则不起作用
所以你需要另一个if(Array.isArray(item.items))的条件

标签： javascript jquery arrays object

【解决方案1】：

我认为您的代码未运行的原因是您的对象格式错误（1 和 2）。除了条件之外，您的代码还可以，因为 trim() 仅适用于字符串类型，因此它在数组上出错。试试这个代码sn-p

function changeObj(obj){
  let result =  obj.reduce(function (acc, item) {
      acc[item.key] = item.items;
      return acc;
    }, {});
  return result;
}

var obj1 = [
 { id:0, items:["SG","AU"], count: 2, key:"countries"},
 { id:1, items:["finance"], count: 3, key:"info"} 
]

var obj2 = [
  { id:0, items: "SG", key: "country"},
  { id:1, items: "details", key: "info"}
]

console.log(changeObj(obj1));

【讨论】：

【解决方案2】：

const changeObj = obj =>
  obj.reduce((acc, item) => {
    if (Array.isArray(item.items)) {
      acc[item.key] = [...item.items, item.count];
    } else {
      acc[item.key] = item.items;
    }
    return acc;
  }, {});

var obj1 = [
  { id: 0, items: ['SG', 'AU'], count: 2, key: 'countries' },
  { id: 1, items: ['finance'], count: 3, key: 'info' }
];

var obj2 = [
  { id: 0, items: 'SG', key: 'country' },
  { id: 1, items: 'details', key: 'info' }
];

console.log(changeObj(obj1));
console.log(changeObj(obj2));

或者清理得更多

const changeObj = obj =>
  obj.reduce((acc, { items, key, count }) => {
    Array.isArray(items) ? (acc[key] = [...items, count]) : (acc[key] = items);

    return acc;
  }, {});

var obj1 = [
  { id: 0, items: ['SG', 'AU'], count: 2, key: 'countries' },
  { id: 1, items: ['finance'], count: 3, key: 'info' }
];

var obj2 = [
  { id: 0, items: 'SG', key: 'country' },
  { id: 1, items: 'details', key: 'info' }
];

console.log(changeObj(obj1));
console.log(changeObj(obj2));

【讨论】：