如何解析正确的 JSON 数据 [重复]

Question

我有这个端点 - https://gbfs.urbansharing.com/oslobysykkel.no/station_information.json

这是回复

{
  "last_updated": 1553592653,
  "data": {
    "stations": [
      {  
        "station_id":"627",
        "name":"Skøyen Stasjon",
        "address":"Skøyen Stasjon",
        "lat":59.9226729,
        "lon":10.6788129,
        "capacity":20
      },
      {  
        "station_id":"623",
        "name":"7 Juni Plassen",
        "address":"7 Juni Plassen",
        "lat":59.9150596,
        "lon":10.7312715,
        "capacity":15
      },
      {  
        "station_id":"610",
        "name":"Sotahjørnet",
        "address":"Sotahjørnet",
        "lat":59.9099822,
        "lon":10.7914482,
        "capacity":20
      }
    ]
  }
}

如何解析数据以仅接收每个对象的此参数？

    "address":"Skøyen Stasjon",
    "lat":59.9226729,
    "lon":10.6788129

我试图做这样的事情

const GbfsClient = require('gbfs-client');
const gbfsClient = new GbfsClient('https://gbfs.urbansharing.com/oslobysykkel.no/');

gbfsClient.stationInfo()
    .then(osloStatus => console.log(osloStatus));

但我也收到了控制台中的所有内容。我不明白如何调用以.json 结尾的端点

谁能给我一个提示，告诉我如何做到这一点。

Answer 1

// Fetch data
fetch("https://gbfs.urbansharing.com/oslobysykkel.no/station_information.json", {
    method: 'GET',
    redirect: 'follow'
})
.then(response => response.json())
.then(result => {

    // For each 'station'
    result.data.stations.forEach((station) => {
    
      // Process data
      console.log(station.address, station.lat, station.lon);
    });
})
.catch(error => console.log('error', error));