【发布时间】:2020-03-24 01:33:00
【问题描述】:
我正在寻找一种 react-native 方法,让用户使用他的电话号码注册,然后添加他的电子邮件和密码。 但是当用户登录时,他只使用电子邮件和密码登录。
电话号码仅出于安全原因。
我在用户验证他的号码后执行 signInWithPhoneNumber() 我调用了 createUserWithEmailAndPassword() 但这是在控制台 Auth 中同时进行的两个单独的身份验证 “电子邮件”和“电话号码”
代码
// I just pass the result into separate screen then use it to confirm all stuff is work :D
...
auth()
.signInWithPhoneNumber(phoneWithAreaCode, true)
.then(confirmResult => {
console.log('2', phoneWithAreaCode);
console.log('confirmResult', confirmResult);
this.setState({
confirmResult,
loading: false,
});
})
...
confirmCode = codeInput => {
const {confirmResult, email, password} = this.state;
console.log('codeInput Is:', codeInput.length);
if (confirmResult && codeInput.length) {
confirmResult
.confirm(codeInput)
.then(async () => {
clearInterval(this.interval);
const {params} = this.props.navigation.state;
await auth()
.createUserWithEmailAndPassword(email, password)
.then(({user}) => {
console.log('hey u');
let uid = user.uid;
params.createUser(uid);
})
.catch(error => {
// Handle Errors here.
var errorCode = error.code;
switch (errorCode) {
case 'auth/email-already-in-use':
this.setState({loading: false, password: ''});
break;
case 'auth/invalid-email':
this.setState({loading: false, password: ''});
break;
case 'auth/operation-not-allowed':
this.setState({loading: false, password: ''});
break;
case 'auth/weak-password':
this.setState({loading: false, password: ''});
break;
default:
this.setState({loading: false, password: ''});
break;
}
});
//Check if any users exist
// database()
// .ref(`users`)
// .limitToFirst(1)
// .once('value', async snapshot => {
// if (snapshot.exists()) {
// console.log('exists!');
// return true;
// } else {
// // params.createUser(user.uid);
// console.log('No user found Hah');
// }
// });
this.setState({
timer: 0,
isValid: true,
});
})
.catch(error => {
let errorCode = error.code;
let errorMessage = error.message;
console.log(errorCode);
switch (errorCode) {
case 'auth/invalid-verification-code':
this.setState({codeInput: ''});
this.refs.codeInputRef2.clear();
break;
default:
break;
}
console.log(errorMessage);
});
} else {
console.log('Not here');
}
};
编辑
confirmCode = codeInput => {
const {confirmResult, password, email} = this.state;
console.log('codeInput Is:', codeInput.length);
if (confirmResult && codeInput.length) {
confirmResult
.confirm(codeInput)
.then(user => {
console.log(user);
let userE = auth().currentUser;
// userE.updateEmail(email);
auth().createUserWithEmailAndPassword(email, password);
clearInterval(this.interval);
const {params} = this.props.navigation.state;
params.createUser(user.uid);
this.setState({
timer: 0,
isValid: true,
});
})
.catch(error => {
let errorCode = error.code;
let errorMessage = error.message;
switch (errorCode) {
case 'auth/invalid-verification-code':
this.refs.codeInputRef2.clear();
break;
default:
break;
}
console.log(errorMessage);
});
} else {
console.log('Not here');
}
};
【问题讨论】:
-
嘿伙计@Dupocas 为什么要删除 firebase-auth 标签?我的问题与他们有关
-
只删除了 react-native 因为它与它没有直接关系。感谢警告
标签: javascript reactjs firebase react-native firebase-authentication