【发布时间】:2017-05-26 23:23:03
【问题描述】:
我有 2 个选择。
Leagues 一个,Divisions 一个
我想创建一个Pipe,它将根据选择的League 过滤Divisions。
给出下面的数据。如果我选择Random Beer League,则只有TwoFour 和SixPack 应显示为Divisions 选择的选项。
leagues = [
{id: 1, leagueName: 'Recreation League' },
{id: 2, leagueName: 'Random Beer League' }
];
divisions = [
{id: 1, divisionName: 'SoGreen', leagueId: 1, leagueName: 'Recreation League' },
{id: 2, divisionName: 'Yellow', leagueId: 1, leagueName: 'Recreation League' },
{id: 3, divisionName: 'TwoFour', leagueId: 2, leagueName: 'Random Beer League' },
{id: 4, divisionName: 'SixPack', leagueId: 2, leagueName: 'Random Beer League' }
];
*注意 - plunker 中的数据是硬编码的,但在我的应用设置中它是 Observable。
【问题讨论】:
标签: javascript angular angular2-pipe