如何在AngularJS中对象的所有属性中搜索字符串

Question

谁能告诉如何在所有属性中搜索字符串。如果某些属性匹配，我需要将对象推送到 AngularJS 的数组中。

我有一个数组

$scope.ListOfPeople = [
    { PersonID: 10, FirstName: "John", LastName: "Smith", Sex: "Male" },
    { PersonID: 11, FirstName: "James", LastName: "Last", Sex: "Male" },
    { PersonID: 12, FirstName: "Mary", LastName: "Heart", Sex: "Female" },
    { PersonID: 13, FirstName: "Sandra", LastName: "Goldsmith", Sex: "Female" },
    { PersonID: 14, FirstName: "Shaun", LastName: "Sheep", Sex: "Male" },
    { PersonID: 15, FirstName: "Nicola", LastName: "Smith", Sex: "Male" }
];

如果用户在搜索文本框中输入了一些值。如果匹配需要推送匹配的对象，我需要使用 PersonID、FirstName、LastName、Sex 和所有属性进行搜索。

Answer 1

我认为 Angular 的 Filter 过滤器可以满足您的需求

<input ng-model="search"/>
<div ng-repeat="person in ListOfPeople | filter:search">
    {{person}}
</div>

Answer 2

类似的东西？

for(var index in $scope.ListOfPeople) { 
   if ($scope.ListOfPeople.hasOwnProperty(index)) {
       if($scope.ListOfPeople[index] == "Your string") {
           // Do something here 
       }
   }
}