ngrx 8影响其他类型的调度动作

Question

我在这里与您联系关于ngrx 效果，我正在尝试做的是有一个功能登录，它分配一个动作类型的登录，并且对这个动作的影响将使用我的服务来进行api 调用。 在这个返回令牌之后，我想分派另外两个动作，一个是 getUserMenu 类型，一个是 getUserInfo 类型。这两个动作的类型不同，效果也不同。

最后我有 3 家商店： 一个用于令牌和身份验证 一个用于用户信息 一个用于菜单信息

我试过这样的事情：

login = createEffect(
  () =>
  this.actions$
  .pipe(
  ofType(authLogin),
    tap(action => {
    console.log("EFFECT LOGINNNN");
    return this.authService.postLogin(action.username, 
      action.password).pipe(
        map((data: any) => {
          console.log("AUTHTHHTHTH DATATA ", data);
          let props = data.token;
          let payload = {
            token: data.token,
            isAuthenticated: true
          }
      this.store.dispatch(moMenuHttpGetListAction({US_ID: action.username}));  
      this.store.dispatch(userHttpGetInfoAction({US_ID:action.username}));
      this.localStorageService.setItem(AUTH_KEY, payload);
    }))
  })
),
{ dispatch: true }
);

如果我设置调度错误登录工作，但没有调用获取用户信息和用户菜单的方法 但是当我设置 dispatch true 我有同样效果的无限循环 动作 moMenuHttpGetListAction 看起来像这样：

moMenuHttpGetListEffect = createEffect(
     () => this.actions$.pipe(
        ofType(moMenuHttpGetListAction),
        switchMap(action => {
          console.log("MOMENU LOGINNNN");

          return this.moMenuService.getKmApplications(action.US_ID).pipe(
          map((data: any) => {
            console.log("MOMENU DATATA ", data);
            console.log("MOMENU DATATA ", action.US_ID);
            let payload = {
              MO_MENU: data
            }

          this.store.dispatch(moMenuSetListAction({payload: data}));
           this.localStorageService.setItem(MENU_KEY, payload);
          }))
        })
        ),
    { dispatch: false }
  );

但是当我将 dispatch 设置为 true 时，我得到了编译错误。 我的动作看起来像：

import { createAction } from "@ngrx/store";
import { props } from "@ngrx/store";
import { MoMenu, MoMenuState } from "./mo_menu.models";

//TODO CHANGER ME_ID en US_ID
export const moMenuGetErrorAction = createAction("[User] Get Info");
export const moMenuGetIsLoadingAction = createAction("[User] Get Info");

export const moMenuSetErrorAction = createAction('[MoMenu] HTTP GET ACTION',
    props<{error: string}>()
    );
export const moMenuSetLoadingAction = createAction('[MoMenu] HTTP GET ACTION',
    props<{loading: boolean}>()
    );
export const moMenuHttpGetListAction = createAction('[MoMenu] HTTP GETLIST  ACTION',
    props<{US_ID: string}>()
    );
export const moMenuHttpGetListErrorAction = createAction('[MoMenu] HTTP GET ACTION Error',
    props<{error: any}>()
    );

export const moMenuGetListAction = createAction("[MoMenu] Get List");
export const moMenuSetListAction = createAction("[MoMenu] Set Mo Menu List",
    props<{payload: MoMenu[]}>());
export const moMenuDeleteAction = createAction("[MoMenu] Delete List");

这是有人要求我补充的两个减速器：

Ngrx 对我来说有点新，所以我很想在这方面提供一些帮助 =)

import { AuthState } from './auth.models';
import { authLogin, 
  authLogout ,
  authGetErrorAction,
  authGetIsLoadingAction,
  authSetErrorAction,
  authSetIsLoadingAction
} from './auth.actions';
import { createReducer, on, Action } from '@ngrx/store';

export const initialState: AuthState = {
  isAuthenticated: false,
  token: undefined,
  isLoading: false,
  HttpResponse: undefined
};

const reducer = createReducer(
  initialState,
    on(authSetErrorAction,  (state, { error }) => ({
    ...state, HttpResponse:  error
  })),
   on(authSetIsLoadingAction,  (state, { isLoading }) => ({
    ...state, isLoading: isLoading 
  })),

  on(authLogin, state => ({ ...state, isAuthenticated: true })),
  on(authLogout, state => ({ ...state, isAuthenticated: false }))
);

export function authReducer(
  state: AuthState | undefined,
  action: Action
): AuthState {
  return reducer(state, action);
}

import { MoMenuState } from "./mo_menu.models";
import { 
  moMenuGetListAction, 
  moMenuDeleteAction,
  moMenuHttpGetListAction,
  moMenuSetListAction,
  moMenuHttpGetListErrorAction,

  moMenuGetErrorAction,
  moMenuGetIsLoadingAction,
  moMenuSetErrorAction,
  moMenuSetLoadingAction
 } from "./mo_menu.actions";
import { createReducer, on, Action } from "@ngrx/store";

export const initialState: MoMenuState = {
    isLoading: false,
  HttpResponse: undefined,
MoMenuItems: null
}

const reducer = createReducer(
  initialState,
  on(moMenuSetErrorAction,  (state, { error }) => ({
    ...state, HttpResponse:  error
  })),
   on(moMenuSetLoadingAction,  (state, { loading }) => ({
    ...state, isLoading: loading 
  })),

  on(moMenuHttpGetListErrorAction, (state, { error }) => (
    undefined)),
   on(moMenuSetListAction, (state, { payload }) => ({
    ...state, MoMenus: payload 
  })),

 on(moMenuHttpGetListAction, (state, { US_ID }) => ({
    ...state
  })),
  on(moMenuGetListAction, state => state),
  on(moMenuDeleteAction, state => state)
);

export function moMenuReducer(
  state: MoMenuState | undefined,
  action: Action
): MoMenuState {
  return reducer(state, action);
}

如果你们中的一些人对我有任何想法？

Answer 1

这就是我在 NgRx 8 中由于另一个操作而分派多个操作的方式：

@Injectable()
export class MyEffects {
    myAction$ = createEffect(() =>
        this.actions$.pipe(
            ofType(myActions.firstAction),
            switchMap(action => this.someService.getById(action.someId)),
            switchMap((sth: Something) => [
                myActions.firstActionSuccess({ payload: sth }),
                myActions.secondAction({ payload: sth.xyz }),
                // ... more actions
            ])
        )
    );

    constructor(
        private someService: SomeService,
        private actions$: Actions
    ) { }
}

动作如下所示：

export const firstAction = createAction('First Action', props<{ someId: number }>());
export const firstActionSuccess = createAction('First Action Success', props<{ payload: Something }>());
export const secondAction = createAction('Second Action', props<{ payload: string }>());

希望有帮助！

Answer 2

您可以这样做以在效果中调度多个操作

@Effect()
    someEffect$: Observable<Action> = this.actions$.pipe(
        ofType<SOME_ACTION>(SOME_ACTION),
        switchMap(_ =>
            of(
                new myAction.Refresh(),
                new myAction.Clear()
                // another action
            )
        )
    );

还要确保有适当的效果来倾听你的动作以使其发挥作用