两次之间增加 30 分钟的间隔

Question

我有根据铁路时间的往返时间，现在我转换为正常时间上午到下午。但在那之后我需要添加 30 分钟的间隔。我对迭代器方法有点困惑。请帮助提前谢谢

我的代码

let fromtime = '09:00:00'

let totime = '21:00:00'

let getGenTime = (timeString) => {
      let H = +timeString.substr(0, 2);
      let h = (H % 12) || 12;
      let ampm = H < 12 ? " AM" : " PM";
      return timeString = h + timeString.substr(2, 3) + ampm;
}

现在我有 am 和 pm 格式的 from 和 to 时间，但我需要在 from 和 to 时间之间添加 30 分钟间隔

  fromtime = getGenTime(fromtime) // 09:00 AM

  totime =  getGenTime(totime)   //  09:00 PM

控制台中的预期结果：

 09:00 AM
 09:30 AM
 10:00 AM
 10:30 AM
 11:00 AM
 ....
 .....
 08:30 PM
 09:00 PM

Answer 1

如果你使用Date 对象而不是strings 会更好，或者使用moment.js 提供许多有用的方法。

但无论如何，它只需要一个带有一些检查的循环来实现你想要的，我创建了一个函数，它将返回一个在你的 fromtime 和 totime 之间的所有时间的数组：

function returnTimesInBetween(start, end) {
  var timesInBetween = [];
  var startH = parseInt(start.split(":")[0]);
  var startM = parseInt(start.split(":")[1]);
  var endH = parseInt(end.split(":")[0]);
  var endM = parseInt(end.split(":")[1]);

  if (startM == 30)
    startH++;
  for (var i = startH; i < endH; i++) {
    timesInBetween.push(i < 10 ? "0" + i + ":00" : i + ":00");
    timesInBetween.push(i < 10 ? "0" + i + ":30" : i + ":30");
  }
  timesInBetween.push(endH + ":00");
  if (endM == 30)
    timesInBetween.push(endH + ":30")

  return timesInBetween.map(getGenTime);
}

演示：

let fromtime = '09:00:00'

let totime = '21:00:00'

let getGenTime = (timeString) => {
  let H = +timeString.substr(0, 2);
  let h = (H % 12) || 12;
  let ampm = H < 12 ? " AM" : " PM";
  return timeString = h + timeString.substr(2, 3) + ampm;
}



function returnTimesInBetween(start, end) {
  var timesInBetween = [];

  var startH = parseInt(start.split(":")[0]);
  var startM = parseInt(start.split(":")[1]);
  var endH = parseInt(end.split(":")[0]);
  var endM = parseInt(end.split(":")[1]);

  if (startM == 30)
    startH++;

  for (var i = startH; i < endH; i++) {
    timesInBetween.push(i < 10 ? "0" + i + ":00" : i + ":00");
    timesInBetween.push(i < 10 ? "0" + i + ":30" : i + ":30");
  }

  timesInBetween.push(endH + ":00");
  if (endM == 30)
    timesInBetween.push(endH + ":30")

  return timesInBetween.map(getGenTime);
}

console.log(returnTimesInBetween(fromtime, totime));

编辑：

要从fromtime 和totime 字符串中获取Date 对象，您可以使用Date 构造函数：

let fromtime = '09:00:00';
var d = new Date(Date.UTC(2017, 10, 10, parseInt(fromtime.split(":")[0]), parseInt(fromtime.split(":")[1])));

请注意区域设置和时区，您可能会在结果中发现几个小时的差异。

演示：

let fromtime = '09:00:00'

let totime = '21:00:00'

let getGenTime = (timeString) => {
  let H = +timeString.substr(0, 2);
  let h = (H % 12) || 12;
  let ampm = H < 12 ? " AM" : " PM";
  return timeString = h + timeString.substr(2, 3) + ampm;
}



function returnTimesInBetween(start, end) {
  var timesInBetween = [];

  var startH = parseInt(start.split(":")[0]);
  var startM = parseInt(start.split(":")[1]);
  var endH = parseInt(end.split(":")[0]);
  var endM = parseInt(end.split(":")[1]);

  if (startM == 30)
    startH++;

  for (var i = startH; i < endH; i++) {
    timesInBetween.push(i < 10 ? "0" + i + ":00" : i + ":00");
    timesInBetween.push(i < 10 ? "0" + i + ":30" : i + ":30");
  }

  timesInBetween.push(endH + ":00");
  if (endM == 30)
    timesInBetween.push(endH + ":30")

  timesInBetween.map(getGenTime);
  return timesInBetween.map(time => new Date(Date.UTC(2017, 10, 10, parseInt(time.split(":")[0]), parseInt(time.split(":")[1]))));
}

console.log(returnTimesInBetween(fromtime, totime));